Java中的随机访问文件中的新行

Question

Whenever using the 'writeBytes' method of RandomAccessFile in java,it writes the text in the same line in the file. How can I get to a new line with RandomAccessFile only? (No BufferedReader ).

Answer 1

You can write a line separator. In order to get the correct line separator for the currently running operating system, you'll have to look for the line.separator property. Something along these lines:

randomAccessFile.writeBytes(System.getProperty("line.separator"));

Answer 2

Try this:

 RandomAccessFile file = new RandomAccessFile("e:\\demo.txt","rw");
 String originalString = "First line \nSeconf line \n";
 String updatedString = originalString.replace("\n","\r\n");
 file.writeBytes(updatedString);

Answer 3

System.getProperty("line.separator");

尝试在文件之前写入新行，因为它将开始写入上次停止写入的位置。

Answer 4

new line character has an ASCII value of 10 . You can store this value in in a Byte and then use the "writeBytes" which will result in a new line.

Answer 5

String data = "New Line";
RandomAccessFile raf = new RandomAccessFile(myFile);
raf.writeBytes("\r\n" + data);

This will add a new line (windows style / CRLF) before the "text".