在WHERE子句中使用CASE

Question

simplified version of my query

SELECT *
FROM logs 
WHERE pw='correct' AND CASE WHEN id<800 THEN success=1 ELSE END 
AND YEAR(timestamp)=2011 

this doesn't work. What i'm trying to do is to add in success=1 only for rows with id<800 , else ignore this check.

how do i write this? thanks!

edit: to clarify, this what the table looks like

|id  | pw      | success |
--------------------------
|700 | correct | 1       |
|710 | correct | 1       |
|900 | correct | NULL    |
|999 | correct | 0       |

I'm trying to return all the rows, the column pw cannot be ignored.

Answer 1

You don't have to use CASE...WHEN, you could use an OR condition, like this:

WHERE
  pw='correct'
  AND (id>=800 OR success=1) 
  AND YEAR(timestamp)=2011

this means that if id<800, success has to be 1 for the condition to be evaluated as true. Otherwise, it will be true anyway.

It is less common, however you could still use CASE WHEN, like this:

WHERE
  pw='correct'
  AND CASE WHEN id<800 THEN success=1 ELSE TRUE END 
  AND YEAR(timestamp)=2011

this means: return success=1 (which can be TRUE or FALSE) in case id<800, or always return TRUE otherwise.

Answer 2

SELECT *
FROM logs
WHERE pw='correct'
  AND CASE
          WHEN id<800 THEN success=1
          ELSE 1=1
      END
  AND YEAR(TIMESTAMP)=2011

Answer 3

This is working Oracle example but it should work in MySQL too.

You are missing smth - see IN after END Replace 'IN' with '=' sign for a single value.

SELECT empno, ename, job
  FROM scott.emp
 WHERE (CASE WHEN job = 'MANAGER' THEN '1'  
         WHEN job = 'CLERK'   THEN '2' 
         ELSE '0'  END) IN (1, 2)

Answer 4

You can transform logical implication A => B to NOT A or B . This is one of the most basic laws of logic. In your case it is something like this:

SELECT *
FROM logs 
WHERE pw='correct' AND (id>=800 OR success=1)  
AND YEAR(timestamp)=2011

I also transformed NOT id<800 to id>=800 , which is also pretty basic.