[英]Checking for special characters and spaces
I have a hangman game created in java. 我有一个用java创建的刽子手游戏。 I want to create a simple function that will check if the word input has white space and/or special characters.
我想创建一个简单的函数来检查单词输入是否有空格和/或特殊字符。
I've found the functions String.replaceAll(), but I haven't been able to dig up a premade function that returns a boolean value for if there are special charactors and/or white space. 我找到了函数String.replaceAll(),但是我还没能找到一个premade函数,它返回一个布尔值,如果有特殊的charactors和/或空格。
Is there a function out there already? 那里有功能吗? Or at least a simpler way of specifying no white space or special characters other than doing the following?
或者至少是一种更简单的方法,除了执行以下操作之外,不指定空格或特殊字符?
public void checkWord()
{
boolean flag = false;
for(int i=0;i<wordArray.length;i++)
{
if(wordArray[i] == '1' || wordArray[i] == '2' || wordArray[i] == '3' || wordArray[i] == '4' || wordArray[i] == '5' || wordArray[i] == '6' || wordArray[i] == '7' || wordArray[i] == '8' || wordArray[i] == '9' )
{
flag = true;
}
}
if(flag == true)
{
System.out.println("Invalid characters used in the word");
System.exit(0);
}
}
The function is getting dense, and I've only covered digits. 功能变得越来越密集,我只覆盖了数字。 Thoughts?
思考?
You can use a simple regular expression: 您可以使用简单的正则表达式:
public boolean isValidWord(String w) {
return w.matches("[A-Za-z]*");
}
Explanation of the regex: 正则表达式的解释:
[A-Za-z] - capital or lowercase letter
* - zero or more
More info on regexes: http://www.regular-expressions.info/ 关于正则表达式的更多信息: http : //www.regular-expressions.info/
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