[英]How to execute on start code in scala Play! framework application?
I need to execute a code allowing the launch of scheduled jobs on start of the application, how can I do this? 我需要执行一个代码,允许在应用程序启动时启动预定作业,我该怎么做? Thanks.
谢谢。
Use the Global
object which - if used - must be defined in the default package: 使用
Global
对象 - 如果使用 - 必须在默认包中定义:
object Global extends play.api.GlobalSettings {
override def onStart(app: play.api.Application) {
...
}
}
Remember that in development mode, the app only loads on the first request, so you must trigger a request to start the process. 请记住,在开发模式下,应用程序仅在第一个请求时加载,因此您必须触发启动该过程的请求。
Since Play Framework 2.6x 自Play Framework 2.6x起
The correct way to do this is to use a custom module with eager binding: 执行此操作的正确方法是使用具有急切绑定的自定义模块:
import scala.concurrent.Future
import javax.inject._
import play.api.inject.ApplicationLifecycle
// This creates an `ApplicationStart` object once at start-up and registers hook for shut-down.
@Singleton
class ApplicationStart @Inject() (lifecycle: ApplicationLifecycle) {
// Start up code here
// Shut-down hook
lifecycle.addStopHook { () =>
Future.successful(())
}
//...
}
import com.google.inject.AbstractModule
class StartModule extends AbstractModule {
override def configure() = {
bind(classOf[ApplicationStart]).asEagerSingleton()
}
}
See https://www.playframework.com/documentation/2.6.x/ScalaDependencyInjection#Eager-bindings 请参阅https://www.playframework.com/documentation/2.6.x/ScalaDependencyInjection#Eager-bindings
I was getting a similar error. 我收到了类似的错误。 Like @Leo said, create Global object in app/ directory.
就像@Leo所说,在app /目录中创建Global对象。
Only thing I had to make sure was to change "app: Application" to "app: play.api.Application". 我唯一需要确定的是将“app:Application”更改为“app:play.api.Application”。
app: Application referred to class Application in controllers package. app:应用程序在控制器包中引用类Application。
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