[英]Template functions as default template parameters
My class declaration begins as follows: 我的类声明如下所示:
template<
class P,
class B,
class comparePosition = compareHorizontal< P >
>
class BlahBlah { ...
where compareHorizontal
is a template function. 其中
compareHorizontal
是模板函数。 When I attempt to compile, clang spits out 当我尝试编译时,c发出声
[...]/entity.hpp:57:33: error: type name requires a specifier or qualifier
class comparePosition = compareHorizontal< P >
^
[...]/entity.hpp:57:33: error: C++ requires a type specifier for all declarations
class comparePosition = compareHorizontal< P >
^~~~~~~~~~~~~~~~~
(and a whole lot of other errors on the same line). (以及同一行上的很多其他错误)。
If I just remove the default template parameter, leaving all else intact, it compiles just fine. 如果我只是删除默认的模板参数,而其他所有参数保持不变,则可以正常编译。 So I wonder, how would I use a function template as a default argument, if that's even possible?
所以我想知道,如果可能的话,我将如何使用函数模板作为默认参数? Or would I be better off just making a functor class with an
operator()
that calls compareHorizontal
and use that instead? 还是只用一个
operator()
来调用functor类,然后调用compareHorizontal
而不是呢?
I think the reason is that the template function is not a type. 我认为原因是模板函数不是类型。 It is a specific value if you think of it, the type of the function goes something like this:
如果您认为它是一个特定的值,则函数的类型如下所示:
template<
class P,
class B,
class C=bool (*)(P&)
>
class BlahBlah {
};
and it compiles. 并编译。 It is as if you said class C=5;
好像您说的是C = 5级; this also will not compile, because 5 is not a type.
这也不会编译,因为5不是类型。 I suggest you use a struct in such case.
我建议您在这种情况下使用结构。
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