[英]RegEx - Find Position of last found symbol in String
i am struggling with regex in Python, i would like to find the position of the last token in a String. 我在Python中使用正则表达式时遇到了麻烦,我想在字符串中找到最后一个标记的位置。
Example: "mydrive/projects/test/version01" 示例:“ mydrive / projects / test / version01”
Now i would like to get the position of the symbol between "test" and "version01" 现在我想获取符号在“ test”和“ version01”之间的位置
import re
txt = "mydrive/projects/test/version01"
p = re.compile("/^.*/(.*)$/")
m = re.search(p, txt)
m.group(0)
#but m.group(0) delivers None
but with this i am getting "None" i tried several things, but couldn't get it find the pattern. 但是与此同时,我遇到了“无”的问题,我尝试了几种方法,但是找不到模式。 By the way i got this regex from a javascript page, but i think the patterns are the same. 顺便说一下,我从一个javascript页面得到了这个正则表达式,但是我认为模式是相同的。
thank you very much! 非常感谢你!
You're using the re
module in the wrong way. 您使用错误的方式使用了re
模块。
You have 2 errors: 您有2个错误:
search.sub
's documentation . search.sub
的文档 。 re
doesn't need the slashes around the regexp. Python的re
不需要正则表达式的斜线。 Either use: 可以使用:
p = re.compile("^.*/(.*)$")
m = p.search(txt)
m.group(0)
Or: 要么:
m = re.search("^.*/(.*)$", txt)
m.group(0)
You say: Now i would like to get the position of the symbol between "test" and "version01". 您说:现在,我想获取符号在“ test”和“ version01”之间的位置。
I don't see how the regex is going to help you much. 我不知道正则表达式将如何帮助您。 You could try the following: 您可以尝试以下方法:
Reverse scan for the symbol, if you know what the symbol is (I am assuming you do, since it is in the regex too): 如果您知道符号是什么,则反向扫描符号(我假设您也这样做,因为它也在正则表达式中):
>>> txt = "mydrive/projects/test/version01"
>>> txt.rfind('/')
21
If you don't know the separator: 如果您不知道分隔符:
>>> import os.path
>>> len(os.path.dirname(txt))
21
I'm curious whether you're wanting to use re
or are actually trying to split that filepath ? 我很好奇您是要使用re
还是实际上是在尝试拆分该文件路径?
os.path
has all you need if that's the case, if not forgive me for answering a non asked question. 如果是这样, os.path
拥有您所需要的一切,如果不能原谅我回答一个未问的问题。
In [212]: import os
In [213]: os.path.split("mydrive/projects/test/version01")
Out[213]: ('mydrive/projects/test', 'version01')
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