使用PHP和HTML显示存储在数据库中的图像

Question

I want to display the Images I've stored in my database in this HTML table. I've stored the files as 'BLOB' and I'd like the Images to be displayed under the 'Photo' column. What code do I use to echo out the images?

    <table wactidth='100%' border='1' cellspacing='0' align="center">
    <thead align='left'>
        <th>Photo</th>
        <th>Act Name</th>   
        <th>Genre</th>
        <th>First Name</th>
        <th>Last Name</th>
        <th>Number of People</th>
        <th>Actions</th>

    </thead>
    <tbody>
    <?php foreach($acts as $act):?>
        <tr>
            <td><!-- I WANT TO DISPLAY THE IMAGES UNDER THIS COLUMN--></td>
            <td><?php echo $act['ActName'];?></td>
            <td><?php echo $act['Genre'];?></td>
            <td><?php echo $act['ContactFirstName'];?></td>
            <td><?php echo $act['ContactLastName'];?></td>
            <td><?php echo $act['NumberOfPeople'];?></td>
            <td><a href="?editact&actid=<?php echo $act['actid'];?>">Edit</a>|<a href="?delete&actid=<?php echo $act['actid'];?>">Delete</a>|<a href="upload&actid=<?php echo $act['actid'];?>">Upload Image</td>
        </tr>
    <?php endforeach?>
    </tbody>
</table>

Answer 1

I would recommend storing just the paths to the images, like "/path/to/your/image.jpg". Then you can echo out the path just like a string

<td><img src="<?php echo $act['imagepath'];?>" alt="" /></td>