正则表达式提取最后一次出现特殊字符后的所有数字

Question

I want to extract all digits after last occurrence of character "-" so for example 311-1974-8 should return me 8 and 311-1974-348 should return 348

edit:

Added clarification from a comment:

actually it's an external tool which provides it's own inbuild functionalists and i have no other option but to use regex to extract this. No JS can be applied :(

Answer 1

This captures the last number.

var str = '311-1974-348';
var matches = str.match(/-(\d+)$/);
var match = matches ? matches[1] : null;
console.log("matched? " + match);

Answer 2

Try matching on /[^-]+$/ , eg:

var s = '311-1974-348';
s.match(/[^-]+$/); // => ["348"]

Answer 3

为什么不简单地分裂呢？

var str = input.split('-').pop();

Answer 4

You mentioned in a comment it's for an external tool so...

-([0-9]+)$

dunno how your tool handles captured groups or anything...

Answer 5

Try this /[0-9]+$/ . It worked on both the inputs you provided.