PHP如何在内部表示字符串？

Question

I have basic PHP question

lets say I have a string "02/03/2013", how is this represented internally in PHP, is it converted to integers or to a Hexadecimal equivalent

when comparing two strings, how does PHP compare them internally?

Thanks for the answer in advance

Answer 1

PHP is written in C. All variables are ZVAL structs.

Please read these tutorials to learn more about the PHP internals and get started with writing extensions.

• Extension Writing Part I: Introduction to PHP and Zend
• Extension Writing Part II: Parameters, Arrays, and ZVALs
• Extension Writing Part III: Resources

Table 1 shows the various types, and their corresponding letter codes and C types which can be used with zend_parse_parameters():

Type      Code    Variable Type
Boolean   b       zend_bool
Long      l       long
Double    d       double
String    s       char*, int
Resource  r       zval*
Array     a       zval*
Object    o       zval*
zval      z       zval*

Answer 2

A PHP string is just a sequence of bytes, with no encoding tagged to it. Visit here for additional info..

Answer 3

Strings are strings. No conversion takes place; your string just happens to contain some digits, which is fine, but PHP doesn't treat it any differently than any other string.

PHP compares strings the same way that any other language would: it goes through the two strings character by character, and looks for the first pair of characters that differ. Once it finds one, the string which had a character with a lower ASCII value (like you'd get from ord() ) is considered as being "less" than the other string.