在 scandir 数组中包含 JUST 文件？

Question

I have an array I'm getting back from scandir, but it contains "." and ".." and I don't want it to.

My code:

$indir = scandir('../pages');
$fileextensions = array(".", "php", "html", "htm", "shtml");
$replaceextensions = str_replace($fileextensions, "", $indir);

I am doing a string replace on the file extensions, thus causing [0] and [1] to appear empty, but they are "." and ".."

array(4) {
[0]=>
string(0) ""
[1]=>
string(0) ""
[2]=>
string(4) "test"
[3]=>
string(4) "home"
}

How would I remove the "." and ".." from the array?

Answer 1

You can use array_filter .

$indir = array_filter(scandir('../pages'), function($item) {
    return !is_dir('../pages/' . $item);
});

Note this filters out all directories and leaves only files and symlinks. If you really want to only exclude only files (and directories) starting with . , then you could do something like:

$indir = array_filter(scandir('../pages'), function($item) {
    return $item[0] !== '.';
});

Answer 2

Fastest way to remove dots as files in scandir

$files = array_slice(scandir('/path/to/directory/'), 2); 

From the PHP Manual

Answer 3

array_diff will do what you're looking for:

$indir = scandir('../pages');
$fileextensions = array(".", "php", "html", "htm", "shtml");
$indir = array_diff($indir, array('.', '..'));
$replaceextensions = str_replace($fileextensions, "", $indir);

http://php.net/manual/en/function.array-diff.php

Answer 4

I am aware erknrio provided an answer for this, but here is a cleaner way of getting an array of files without directories (modified to be more efficient):

$dirPath = 'dashboard';

$dir = scandir($dirPath);

foreach($dir as $index => &$item)
{
    if(is_dir($dirPath. '/' . $item))
    {
        unset($dir[$index]);
    }
}

$dir = array_values($dir);

Answer 5

You can use this snippet. It returns just files in directory:

function only_files($dir_element) {
    if (!is_dir($dir_element)) {
        return $dir_element;
    }
}

function givemefiles($dir) {
    $scanned_dir = scandir($dir);
    return array_filter($scanned_dir, "only_files");
}

$dir_path = '../pages';

givemefiles($dir_path);
echo "<pre>";
var_dump($scanned_dir);
echo "</pre>";

Answer 6

simply use preg_replace to remove all kind of hidden's file from directory

$files = array(".", "..", "html", ".~html", "shtml");    
$newfiles = preg_grep('/^([^.])/', scandir($files));

Answer 7

If you need a clean function;

function getFiles($dir){
    return array_values(array_filter(scandir($dir), function($file){
        global $dir;
        return !is_dir("{$dir}/{$file}");
    }));
}

I think this function is both neat and will work well. Also, the keys of the returned array in this function are sorted correctly.

Answer 8

All other answers are good. I have a clean workaround that worked for me.

Use glob function that takes a regex and returns only files that match. It seems to exclude the . and .. directories, so using a simple

$indir = glob('../pages/*');

should work well.

Answer 9

function dscan( $path ){
     global $dfiles;
     if( !isset( $dfiles ) ){
       $dfiles = array();
     }
     $files = preg_grep('/^.*\.php$/i', scandir($path));
     foreach( $files as $file ){
       if( !in_array( "$path/$file",$dfiles ) ){
         $dfiles[] = array( 'path' => "$path/$file", 'name' => $file );
       }
     }
     return $dfiles;
   }
   dscan( $path );
   print_r( $dfiles );