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在android中从电话簿中选择联系人

[英]Picking a Contact from phone book in android

I want to pick a contact from the phone book in android. 我想从android电话簿中选择一个联系人。 I press a button and then it shows the contact list. 我按下一个按钮,然后显示联系人列表。 When I click I want to pick that clicked contact's number displayed in my activity, but in my case it returned null. 当我单击时,我想选择我的活动中显示的该单击的联系人的电话号码,但就我而言,它返回null。 Here is my code: 这是我的代码:

    import android.app.Activity;
    import android.content.Intent;
    import android.database.Cursor;
    import android.net.Uri;
    import android.os.Bundle;
    import android.provider.Contacts.People;
    import android.provider.ContactsContract.Contacts;
    import android.provider.ContactsContract.PhoneLookup;
    import android.view.Menu;
    import android.view.View;
    import android.view.View.OnClickListener;
    import android.widget.Button;
    import android.widget.TextView;

    public class Main extends Activity {
    Button b;
    TextView tv;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        tv = (TextView) findViewById(R.id.textView1);
        b = (Button) findViewById(R.id.button1);
        b.setOnClickListener(new OnClickListener() {

            @Override
            public void onClick(View arg0) {
                // TODO Auto-generated method stub
                Intent intent = new Intent(Intent.ACTION_PICK,People.CONTENT_URI);
                startActivityForResult(intent, 100);
            }
        });
    }

    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        // Inflate the menu; this adds items to the action bar if it is present.
        getMenuInflater().inflate(R.menu.activity_main, menu);
        return true;
    }
    @Override
    protected void onActivityResult(int requestCode, int resultCode, Intent data) {
        super.onActivityResult(requestCode, resultCode, data);
        Uri contact = data.getData();
        Cursor c = managedQuery(contact, null, null, null, null);
        c.moveToFirst();
        tv.setText(c.getString(c.getColumnIndex(People.NUMBER))+" Added");
    }

}

Why this is happening? 为什么会这样呢? Thanks in advance. 提前致谢。

instead of using People.CONTENT_URI use ContactsContract.Contacts.CONTENT_URI 而不是使用People.CONTENT_URI,请使用ContactsContract.Contacts.CONTENT_URI
that is instead of 那不是

 Intent intent = new Intent(Intent.ACTION_PICK,People.CONTENT_URI);

use 采用

 Intent intent = new Intent(Intent.ACTION_PICK,ContactsContract.Contacts.CONTENT_URI);

example : Getting Contact Phone Number 示例: 获取联系电话

your onacitivityResult: 您的onacitivityResult:

  Uri contact = data.getData();
      ContentResolver cr = getContentResolver();

    Cursor c = managedQuery(contact, null, null, null, null);
    //      c.moveToFirst();


    while(c.moveToNext()){
        String id = c.getString(c.getColumnIndex(ContactsContract.Contacts._ID));

        String name = c.getString(c.getColumnIndex(ContactsContract.Contacts.DISPLAY_NAME));
        if (Integer.parseInt(c.getString(c.getColumnIndex(ContactsContract.Contacts.HAS_PHONE_NUMBER))) > 0) {
            Cursor pCur = cr.query(Phone.CONTENT_URI,null,Phone.CONTACT_ID +" = ?", new String[]{id}, null);

            while(pCur.moveToNext()){
                String phone = pCur.getString(pCur.getColumnIndex(Phone.NUMBER));
                tv.setText(name+" Added " + phone);
            }
        }

    }

Did you try to pick different contacts? 您是否尝试选择其他联系人? this may be stupid, but maybe that contact doesn't have a number? 这可能是愚蠢的,但也许那个联络人没有电话?

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