[英]Serialize object to XML based on existing XSD schema
I have to create an XML document that would be based on an certain XML Schema Document. 我必须创建一个基于某个XML Schema Document的XML文档。 Since my data is a
DataSet
, I need to find the best way to start off. 由于我的数据是
DataSet
,因此我需要找到最佳的开始方法。
I have couple of different ideas how to start: 我有几个不同的想法如何开始:
DataSet
into a class that would match the schema document and serialize it DataSet
转换为与架构文档匹配并进行序列化的类 Is this a right way to get a XML output from DataSet
to match XSD schema? 这是从
DataSet
获取XML输出以匹配XSD模式的正确方法吗?
May be you should give XMLBeans a try... It's a diverse framework for playing around with compiled XSD schemas. 也许您应该尝试一下XMLBeans。这是一个用于处理已编译XSD架构的多样化框架。 Compiled in this context means, you create JAVA classes from your XSD-files.
在这种情况下编译意味着您可以从XSD文件创建JAVA类。
Compilation example (as can be seen here ) scomp -out purchaseorder.jar purchaseorder.xsd
汇编例子(如可以看到这里 )
scomp -out purchaseorder.jar purchaseorder.xsd
With this jar in your classpath you could create new a priori valid instances of your schema with something like: 在您的类路径中使用此jar时,您可以使用以下内容创建新的模式的先验有效实例:
public PurchaseOrderDocument createPO() {
PurchaseOrderDocument newPODoc = PurchaseOrderDocument.Factory.newInstance();
PurchaseOrder newPO = newPODoc.addNewPurchaseOrder();
Customer newCustomer = newPO.addNewCustomer();
newCustomer.setName("Doris Kravitz");
newCustomer.setAddress("Bellflower, CA");
return newPODoc;
}
You can find the whole example at: XMLBeans Tutorial under the heading "Creating New XML Instances from Schema". 您可以在以下位置找到整个示例: XMLBeans教程 ,标题为“从模式创建新的XML实例”。
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