如何使用jackson将java对象序列化为xml属性？

Question

is there a way to serialize a java var (eg int) via jackson as an xml attribute? I can not find any spezific jackson or json annotation (@XmlAttribute @javax.xml.bind.annotation.XmlAttribute) to realize this.

eg

public class Point {

    private int x, y, z;

    public Point(final int x, final int y, final int z) {
        this.x = x;
        this.y = y;
        this.z = z;
    }

    @javax.xml.bind.annotation.XmlAttribute
    public int getX() {
        return x;
    }
    ...
}

What I want:

<point x="100" y="100" z="100"/>

but all I got is:

<point>
    <x>100</x>
    <y>100</y>
    <z>100</z>
</point>

Is there a way to get attributes instead of elements? Thanks for help!

Answer 1

Okay I found a solution.

It wasn't necessary to register an AnnotaionIntrospector if you use jackson-dataformat-xml

File file = new File("PointTest.xml");
XmlMapper xmlMapper = new XmlMapper();
xmlMapper.writeValue(file, new Point(100, 100, 100));

The missing TAG was

@JacksonXmlProperty(isAttribute=true)

so just change the getter to:

@JacksonXmlProperty(isAttribute=true)
public int getX() {
    return x;
}

and it works fine. Just follow this how to:

https://github.com/FasterXML/jackson-dataformat-xml

@JacksonXmlProperty allows specifying XML namespace and local name for a property; as well as whether property is to be written as an XML element or attribute.

Answer 2

Have you registered JaxbAnnotationIntrospector ?

ObjectMapper mapper = new ObjectMapper();
AnnotationIntrospector introspector = new JaxbAnnotationIntrospector();
// make deserializer use JAXB annotations (only)
mapper.getDeserializationConfig().setAnnotationIntrospector(introspector);
// make serializer use JAXB annotations (only)
mapper.getSerializationConfig().setAnnotationIntrospector(introspector);