Linux Bash脚本：如何获取没有路径的文件？

Question

I am trying to write a very very simple script in Linux.
Let me show you the code first:

#!/bin/bash
# The shell program uses glob constructs and ls
# to list all entries in testfiles, that have 2
# or more dots "." in their name.

ls -l /path/to/file/*.*.*

When I run this code with bash myscript command, I get something like: /path/to/file/file.with.three.dots

But I don't want this. I want to show only the file name, not the path.
Then I tried:

ls -l *.*.*

But this time is shows me the files, only if I am inside the /path/to/file/.
How can I set the path, so when running the script from any place, it will output the name of the files in the /path/to/file/?

Thank you!

Answer 1

basename path/to/file.bc should give you file.bc

However re-reading the question, I think a temporary cd to the path and then an ls may be better:

(cd /path/to/file; ls -l *.*.*)

Answer 2

Code first:

ls -l /path/to/file/*.*.* | awk -F '/' '{print $NF}'

Now explanation: You list file of your choice and then use awk on it. Switch -F will determine character you use for split (/ in this case). Then you print with awk the value of "$NF", which means "the last one". So you have: /path/to/file/file.with.three.dots. Split it, take the last one (file.with.three.dots) and print it (regardless how long/deep is your path) and without any need of changing your current position on file system.

I really hope, I've helped.

Answer 3

或者使用find命令。

$> find /path/to/file -printf %f\\n\\r

Answer 4

I suggest sticking with basename.

ls -1 /path/to/file/*.*.* | while read path
do
    basename "$path"
done

Its best to use while read rather than for path in $(ls /path/ )* only because if your paths happen to have a space in them the for loop will segment the path.

Answer 5

I used a variation on Zapatero's technique to capture the base file name in an environment variable. $1 is the command-line argument that, by definition in my script, is the full path to the filename in question.

Note that if the full path contains wildcards and returns multiple results, the basename variable will be set to the "last" matching filename, in whatever order ls returns them.

basename=$(ls -1 "$1" | while read path; do basename "$path"; done)