[英]generating new column in grid view for checkbox column
i am using datatable as data source for grid view 我正在使用数据表作为网格视图的数据源
DataTable table = new DataTable();
table.Columns.Add("Dosage", typeof(int));
table.Columns.Add("Drug", typeof(string));
table.Columns.Add("Patient", typeof(string));
table.Columns.Add("Select",typeof(bool));
//
// Here we add five DataRows.
//
table.Rows.Add(25, "Indocin", "David");
table.Rows.Add(50, "Enebrel", "Sam");
table.Rows.Add(10, "Hydralazine", "Christoff");
table.Rows.Add(21, "Combivent", "Janet");
table.Rows.Add(100, "Dilantin", "Melanie");
GridView2.DataSource = table;
GridView2.DataBind();
at page load and i want to create new column in grid to add radio button 在页面加载时,我想在网格中创建新列以添加单选按钮
actually i want to submit row values for selected check boxes in database.. 实际上我想提交数据库中选定复选框的行值。
If you want to add a new column to the GridView
you should add it to it's DataSource
. 如果要向GridView
添加新列,则应将其添加到DataSource
。 Either by selecting another column from the database or, if you use an in-memory DataTable
as here- by adding another DataColumn
. 通过从数据库中选择另一列,或者,如果您按此方式使用内存中的DataTable
,则可以通过添加另一个DataColumn
。 But i assume that you already have added the column( Select
). 但是我认为您已经添加了列( Select
)。
Then use a TemplateField
to add the RadioButton
and eval/bind it to the column. 然后使用TemplateField
添加RadioButton
并将其eval / bind到列中。
<asp:GridView ID="GridView2" runat="server" AutoGenerateColumns="False" OnRowDataBound="GridView2_RowDataBound" >
<Columns>
<asp:TemplateField HeaderText="Select">
<ItemTemplate>
<asp:RadioButton ID="rbSelect" runat="server" />
</ItemTemplate>
</asp:TemplateField>
You can use RowDataBound
to check it according to the datasource: 您可以使用RowDataBound
根据数据源对其进行检查:
protected void GridView2_RowDataBound(object sender, GridViewRowEventArgs e)
{
if (e.Row.RowType == DataControlRowType.DataRow)
{
var rbSelect = (RadioButton)e.Row.FindControl("rbSelect");
var row = ((DataRowView)e.Row.DataItem).Row;
rbSelect.Checked = row.Field<bool>("Select");
}
}
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