用PHP将MySQL结果分组

Question

I am having the following script that takes the results from 3 tables based on a field called "order_id" in all tables.

$sql = "SELECT 
o.order_id, 
order_product.model,
o.name, 
o.value, 
GROUP_CONCAT(o.order_id, order_product.model, o.name, o.value SEPARATOR ',') AS Options 
FROM `order_option` AS o 
LEFT JOIN `order` AS oo on o.order_id = oo.order_id
LEFT JOIN order_product ON o.order_id = order_product.order_id
where oo.order_status_id = 2 
group by oo.order_id";

$result = mysql_query($sql); 
while($row = mysql_fetch_assoc($result))
 {
$options=$row['Options'];
print "|$options|";

    PRINT "<br>-------------------<br>";
} 

The problem is that in table "order_option" there are 2 or more rows with options for each order_id.

The results printed by the script is:

ID, Model, option1:Value, ID, Model, option2:Value

And what I need is:

ID, MODEL, OPTION1:Value, OPTION2:Value

So, no duplication of ID and MODEL for every row.

Any suggestions how can I achieve that?

Answer 1

The problem is with how you're implementing GROUP_CONCAT . You have 2 rows in your Order_Option table that have different options with the same option id. Something like:

OrderId    Name     Value
1          Option1  Value1 
1          Option2  Value2

Using GROUP_CONCAT(OrderId, Name, Value) will concatenate all those fields like:

1, Option1, Value1, 1, Option2, Value2

Instead, you want to retrieve your OrderId on it's own:

SELECT OrderId, GROUP_CONCAT(Name, Value)...

This will give you:

1, Option1, Value1, Option2, Value2

And then the rest is just in your presentation logic.

Good luck.