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[英]directly increment or decrement number update from column using Laravel Eloquent
[英]decrement an auto increment column?
好的,所以我有这个脚本,该脚本可以将值更新或插入到mysql中,还可以自动递增列并将枚举值从0设置为1。
现在我正在尝试找出如何将其反转,以便将枚举值设置回0(我认为我知道该怎么做),我还需要弄清楚如何减量或与增量相反的方式。 ,是否可以在自动递增列中为-1?
只要我可以递减自动递增列并将枚举值从1更改为0,就不必删除这些值。
谁能告诉我我该怎么做? 谢谢。
<?php
require_once('includes/session.php');
require_once('includes/functions.php');
require('includes/_config/connection.php');
session_start();
confirm_logged_in();
if (isset ($_GET['to'])) {
$user_to_id = $_GET['to'];
}
if (!isset($_GET['to']))
exit('No user specified.');
$user_id = $_GET['to'];
$result = mysql_query("SELECT * FROM ptb_likes WHERE liked_id ='".$user_to_id."' ");
if( mysql_num_rows($result) > 0) {
mysql_query("UPDATE ptb_likes SET likes = likes +1 WHERE liked_id = '".$user_to_id."' ");
$user_to_id = mysql_query("ALTER TABLE likes AUTO_INCREMENT = $id");
}
else
{
mysql_query("INSERT INTO ptb_likes (user_id, liked_id) VALUES (".$_SESSION['user_id'].", ".$user_to_id.")");
}
if($result)
{
mysql_query("UPDATE ptb_likes SET user_id_has_liked='1' WHERE user_id=".$_SESSION['user_id']."")
or die(mysql_error());
header("Location: {$_SERVER['HTTP_REFERER']}");
}
?>
如其他建议
create table b
(
id int not null auto_increment primary key,
foo boolean not null
);
insert into b (foo) values (true), (false), (false), (true), (true);
update b set
foo = not foo;
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