在Android中解析复杂的JSON

Question

伙计们，我正在尝试解析以下JSON

{"response": 
{"message": "Success", 
"code": 2002, 
"payload": 
    {"article": [
                    {"timestamp_epoch": 1359967680, 
                    "search_score": 10.0, 
                    "headline": "When Sachin felt like bunking cricket practice", 
                    "timestamp": "2013-02-04 08:48:00", 
                    "related_article_count": 0, 
                    "excerpt": "...their campaign 'Support my School' by NDTV in Mumbai on Sunday. Sachin Tendulkar and Aishwarya Rai Bacchan during an event 3/5 Sachin Tendulkar and Aishwarya Rai Bacchan during an event India's Sachin Tendulkar with actress Aishwarya Rai Bachchan during the...", 
                    "source": {"name": "OneIndia", 
                                "url": "http://www.oneindia.in/", 
                                "daylife_url": "http://www.daylife.com/source/OneIndia", 
                                "rank": 3, 
                                "favicon_url": "http://favicon.daylife.com/imageserve/0e0Jd1Xczb7oW/favicon.png", 
                                "source_id": "0e0Jd1Xczb7oW", 
                                "type": "MAINSTREAM"}, 
                    "url": "http://feedproxy.google.com/~r/oneindia-cricket/~3/z1pS6w289SU/when-sachintendulkar-felt-like-bunking-cricket-practice-066016.html", 
                    "daylife_url": "http://www.daylife.com/article/07nC5eTbBE0YA", 

                    "article_id": "07nC5eTbBE0YA"}, 


                    {"timestamp_epoch": 1360361400, 
                    "search_score": 8.69279902947, 
                    "headline": "Sachin equals Sunny",
                           .
                           .
                           .
                           .
                           .

我只是对标题和网址值感兴趣。 我可以通过下面的Java代码轻松获取这些值。

JSONObject root = new JSONObject(result);
            JSONObject response = root.getJSONObject("response");

            String attributeId = response.getString("message");
            System.out.println(attributeId);

            JSONObject payload = response.getJSONObject("payload");
            JSONArray article = payload.getJSONArray("article");



            for (int i = 0; i < article.length(); i++) {
                JSONObject c = article.getJSONObject(i);
                String headline = c.getString("headline");
                String url = c.getString("url");
                System.out.println(url);
                System.out.println(headline);
                strings.add(c.getString("headline").toString());
            }
            arrayAdapter = new ArrayAdapter<String>(MainActivity.this,
                    android.R.layout.simple_list_item_1, strings);

            resultList.setAdapter(arrayAdapter);
            arrayAdapter.notifyDataSetChanged();

在这里，我在ListView中设置标题 （此部分工作正常）。 我的问题是：当我单击任何列表时，它应该将相应的URL传递给WebView活动（实际上，我正在另一个类中实现此功能）。 那么如何实现这一点，如何用标题存储相应的URL？ 请有人帮我..

提前致谢..

Answer 1

您可以创建一个名为Article的类，该类具有两个属性（字符串标题和字符串url）。 然后为这两个属性生成getter / setter。 现在创建一个Article类型的ArrayList。

ArrayList<Article> articleList = new ArrayList<Article>();

然后在解析数据时按以下方式操作：

Article article = new article();

并将价值放入对象之类的..

article.setHeading(c.getString("headline"));
article.setUrl(c.getString("url"));

并将对象添加到arraylist之类的..

articleList.add(article);

毕竟，当单击任何列表项时，要使它变得吓人，请在您的主要活动中添加OnItemClickListener。 它将为您提供被点击项目的位置。 那么您可以从arcleList之类的网站获取相应对象的网址。

articleList.setOnItemClickListener(new OnItemClickListener() {

        @Override
        public void onItemClick(AdapterView<?> arg0, View arg1, int position,
                long id) {
            String url = articleList.get(position).getUrl();
            Intent i = new Intent(MainActivity.this,   WebViewActivity.class);
            i.putExtra("url", url);
            startActivity(i);
        }
    });

现在将此网址放入主要活动的意图中，并将其接收到webActivity中，并最终在webView中使用它...

Answer 2

创建一个自定义的Adapter，将URL，Headline作为模型存储并在onView中显示标题文本，并在listview的onitemclicklistener中访问适配器中的模型obj，并使用该URL打开Webview ...，例如http：//www.ezzylearning。 com / tutorial.aspx？tid = 1763429

和itemclick侦听器

listView.setOnItemClickListener(new android.widget.AdapterView.OnItemClickListener() {

  public void onItemClick(AdapterView<?> parent, View view,int position, long id) {
  Model item = (Model)contests_listView.getItemAtPosition(position);  
  Intent browserIntent = new Intent(Intent.ACTION_VIEW, Uri.parse(item.getUrl()));
  startActivity(browserIntent);  // show url in browser  or pass it to your webview activity

     }
 });