从table2中缺少table2的行中获取行？

Question

我有两个下表。 正在使用Oracle 10g

TableA
---------
id  Name
--- ----
1   abc
2   def
3   xxx
4   yyy

TableB
---------
id  Name
--- ----
1   abc
2   def

TableC
---------
id  Name
--- ----
1   abc
2   def

现在，我需要from TableA which are not there in TableB and TableC获取from TableA which are not there in TableB and TableC的ID。 不使用NOT IN子句怎么办？

请帮我！

谢谢！

Answer 1

请试试：

SELECT 
  a.ID, 
  a.NAME
FROM 
  TABLEA a LEFT JOIN TABLEB b ON a.ID=b.ID 
    LEFT JOIN TABLEC c ON a.ID=c.ID
WHERE 
  b.ID IS NULL AND 
  c.ID IS NULL;

Answer 2

select * from TableA
minus
select * from TableB

---

编辑：

同时不在B和C中的内容：

select * from TableA
minus (
  select * from TableB
  intersect
  select * from TableC
)

不在B或C中的：

select * from TableA
minus 
select * from TableB
minus
select * from TableC

Answer 3

select a.id
from tableA a,tableB b,tableC c
where a.id != b.id and a.id!=c.id 

这样好吗

Answer 4

select * from TableA
minus
(select * from TableB
union
select * from TableC)