繁体   English   中英

pthread广播然后等待?

[英]pthread broadcast and then wait?

我正在尝试设置几个线程以处于等待状态,直到它们收到pthread_cond_broadcast()

完成一项工作后,我希望线程回到等待状态。

我还希望调用pthread_cond_broadcast()的进程在继续之前等待所有线程返回其等待状态。 在这种情况下,它是调用广播的main()函数。 我正在尝试做这个b有main(0在调用广播后做一个pthread_cond_wait()

void* Work::job(void* id)
{
    int idx = (long)id;

    while(1)
    {
        pthread_mutex_lock(&job_lock);

        while(!jobs_complete)
        {
            // wait for main to broadcast
            pthread_cond_wait(&can_work, &job_lock);
            pthread_mutex_unlock(&job_lock);

            // work here

            pthread_mutex_lock(&job_lock);
            ++jobs_completed;

            if(jobs_completed == NUM_THREADS)
            {
                jobs_complete = true;
                pthread_cond_signal(&jobs_done);
                pthread_mutex_unlock(&job_lock);
            }
            pthread_mutex_unlock(&job_lock);
        }

        pthread_mutex_unlock(&job_lock);
    }

    return NULL;
}

NUM_THREADS为4, job_lockpthread_mutex_tcan_workjobs_donepthread_cond_tjobs_completedbooljobs_completeint

// work

jobs_completed = false;
jobs_complete = 0;
pthread_mutex_lock(&job_lock);
pthread_cond_broadcast(&can_work);
pthread_cond_wait(&jobs_complete);
pthread_mutex_unlock(&job_lock);

// work that depends on jobs_complete

现在,我现在这样做的权利,通过调用pthread_cond_broadcast()然后pthread_cond_wait()之后,但这个好像死锁。

任何人都可以解释我应该如何做这个或我出错的地方? 我很感激你的帮助。

谢谢!

我只发布这个(这几乎都是C代码,但pthreads也是如此,所以请求一点松弛)来演示一种做我认为你想要完成的事情的方法。 显然,您希望将大部分内容正确地封装在适当的类中等。这有望向您展示条件变量,互斥体及其与谓词管理和通知的关系是如何工作的。

希望对你有帮助。 祝你有美好的一天。

#include <iostream>
#include <unistd.h>
#include <pthread.h>
using namespace std;

// our global condition variable and mutex
pthread_cond_t cv = PTHREAD_COND_INITIALIZER;
pthread_mutex_t mtx = PTHREAD_MUTEX_INITIALIZER;

// our predicate values.
bool finished = false;
int jobs_waiting = 0;
int jobs_completed = 0;

// our thread proc
static void *worker_proc(void* p)
{
    intptr_t id = (intptr_t)p;  // our id
    size_t n_completed = 0;     // our job completion count

    // always latch prior to eval'ing predicate vars.
    pthread_mutex_lock(&mtx);
    while (!finished)
    {
        // wait for finish or work-waiting predicate
        while (!finished && jobs_waiting == 0)
            pthread_cond_wait(&cv, &mtx);

        // we own the mutex, so we're free to look at, modify
        //  etc. the values(s) that we're using for our predicate
        if (finished)
            break;

        // must be a job_waiting, reduce that number by one, then
        //  unlock the mutex and start our work. Note that we're
        //  changing the predicate (jobs_waiting is part of it) and
        //  we therefore need to let anyone that is monitoring know.
        --jobs_waiting;
        pthread_cond_broadcast(&cv);
        pthread_mutex_unlock(&mtx);

        // DO WORK HERE (this just runs a lame summation)
        for (int i=0,x=0;i<1048576; x += ++i);
        ++n_completed;

        // finished work latch mutex and setup changes
        pthread_mutex_lock(&mtx);
        ++jobs_completed;
        pthread_cond_broadcast(&cv);
    }

    // final report
    cout << id << ": jobs completed = " << n_completed << endl;

    // we always exit owning the mutex, so unlock it now. but
    //  let anyone else know they should be quitting as well.
    pthread_cond_broadcast(&cv);
    pthread_mutex_unlock(&mtx);
    return p;
}

// sets up a batch of work and waits for it to finish.
void run_batch(int num)
{
    pthread_mutex_lock(&mtx);
    jobs_waiting = num;
    jobs_completed = 0;
    pthread_cond_broadcast(&cv);

    // wait or all jobs to complete.
    while (jobs_completed != num)
        pthread_cond_wait(&cv, &mtx);

    // we own this coming out, so let it go.
    pthread_mutex_unlock(&mtx);
}

// main entry point.
int main()
{
    // number of threads in our crew
    static const size_t N = 7;
    pthread_t thrds[N] = {0};

    // startup thread crew.
    intptr_t id = 0;
    for (size_t i=0; i<N; ++i)
        pthread_create(thrds + i, NULL, worker_proc, (void*)(++id));

    // run through batches. each batch is one larger
    //  than the prior batch. this should result in some
    //  interesting job-counts per-thread.
    for (int i=0; i<64; ++i)
        run_batch(i);

    // flag for shutdown state.
    pthread_mutex_lock(&mtx);
    finished = true;
    pthread_cond_broadcast(&cv);
    pthread_mutex_unlock(&mtx);
    for (size_t i=0; i<N; pthread_join(thrds[i++], NULL));

    return 0;
}

样本输出#1

3: jobs completed = 256
6: jobs completed = 282
5: jobs completed = 292
2: jobs completed = 242
1: jobs completed = 339
4: jobs completed = 260
7: jobs completed = 409

样本输出#2

6: jobs completed = 882
1: jobs completed = 210
4: jobs completed = 179
5: jobs completed = 178
2: jobs completed = 187
7: jobs completed = 186
3: jobs completed = 194

样本输出#3

1: jobs completed = 268
6: jobs completed = 559
3: jobs completed = 279
5: jobs completed = 270
2: jobs completed = 164
4: jobs completed = 317
7: jobs completed = 159

固定批量大小

相同的代码,但更改此:

for (int i=0; i<64; ++i)
    run_batch(i);

对此:

for (int i=0; i<64; ++i)
    run_batch(N);

给出以下内容,这可能更接近您真正想要的内容。

样本输出#1

4: jobs completed = 65
2: jobs completed = 63
5: jobs completed = 66
3: jobs completed = 63
1: jobs completed = 64
7: jobs completed = 63
6: jobs completed = 64

样本输出#2

3: jobs completed = 65
5: jobs completed = 62
1: jobs completed = 67
7: jobs completed = 63
2: jobs completed = 65
6: jobs completed = 61
4: jobs completed = 65

样本输出#3

2: jobs completed = 58
4: jobs completed = 61
5: jobs completed = 69
7: jobs completed = 68
3: jobs completed = 61
1: jobs completed = 64
6: jobs completed = 67

在函数末尾有3个可能的连续调用pthread_mutex_unlock ,这将导致未定义的行为。 你实际上并不需要两个内在的。 如果jobs_completetrue ,则线程将退出循环并释放锁定,否则它将循环并需要它来等待can_work条件。

还有,那里

 pthread_cond_wait(&jobs_complete);

你可能意味着:

pthread_cond_wait(&jobs_complete,&job_lock);

此外,该函数需要一个pthread_cond_t *和一个pthread_mutex_t * ,而不是一个int ,所以即使这样,代码也明显被破坏了。

要知道,一个信号或条件变量广播只会对已经在等待此变量线程的效果。 信号不会保留以供将来等待。 因此,当线程在jobs_complete时再次循环jobs_complete并再次等待时,必须再次发出信号以恢复工作。

另一件事:你提到job_complete的类型为intjob_completedbool ,但你的代码似乎不同意:

        if(jobs_completed == NUM_THREADS)
        {
            jobs_complete = true;

这是我的建议:学习信号量和屏障抽象模型,如果可以的话,使用现有的实现(C ++ 11中的booststd ),或者使用pthread API重新实现它们。 这些将帮助您比操纵cond变量更容易处理这种情况。 在这个网站上查找现有解决方案。 例如, 这个问题涉及一个非常类似的问题,我提供的解决方案可以很容易地修改,以使用pthread API来满足您的要求。

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM