[英]How to constuct a MySQL query which will return a flag, either returning y or n based on the rows in another table?
[英]MySQL query to return rows which are not listed in another table
我在MySQL DB PHPMyAdmin中有两个表:
Table-1: T1
Table-2: T2
我需要编写一个mysql查询,该查询将从T1
返回所有未在T2
列出的IMEI。
例如,在这种情况下,查询应返回123456781235176
。
谢谢。
尝试select IMEI from T1 where IMEI not in (select IMEI from T2);
SELECT t1.* FRO table1 AS t1
LEFT JOIN table2 AS t2 ON t1.IMEI = t2.IMEI
WHERE t2.IMEI IS NULL
试试这个查询
Select EMEI from t1 where EMEI not in (select EMEI from t2)
select IMEI from T1 where IMEI not in
(
select a.IMEI from T1 as a inner join T2 as b on a.IMEI = b.IMEI
) as exp
希望这个能对您有所帮助
SELECT IMEI FROM T1 WHERE IMEI NOT IN(SELECT IMEI FROM T2);
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