Mysql查询，PHP计数

Question

我有一个MySQL第一个表的以下结构：

http://www.clubmadam.com/zadatak.jpg

MySQL第二个表的结构：

http://www.clubmadam.com/country.jpg

我需要一个SQL查询来计算每个国家/地区的城市数量，并总结国家/地区所有城市的人口数量;

这是我到目前为止：

$upit = "SELECT";
$rezultat = mysql_query($upit);
{
}

MySQL可以处理这个，还是我还需要使用PHP？ 我该怎么做？

Answer 1

这真的是SQL 101的东西，我建议你做很多阅读

SELECT CountryCode,
       COUNT(Name) as Cities,
       SUM(Population) as Population
  FROM <tablename>
 GROUP BY CountryCode

Answer 2

如果我理解正确，此查询将根据国家/地区计算城市数量：

SELECT COUNT(*) AS CityCount, CountryCode, SUM(Population) AS CountryPopulation
FROM myTableName
GROUP BY CountryCode

根据您的评论，以下是如何跨多个表执行此操作：

SELECT City.COUNT(*) AS CityCount, Country.LocalName, City.SUM(Population) AS CountryPopulation
FROM City, Country
GROUP BY City.CountryCode

Answer 3

这是一个使用SUM()和COUNT() 聚合函数的简单MySQL聚合作业：

$sql = 'SELECT 
  CountryCode, 
  COUNT(ID) as numCities, 
  SUM(Population) as totalPopulation 
  FROM Cities 
  GROUP BY CountryCode';

Answer 4

$upit = "SELECT COUNT(ID) AS cities, SUM(Population) AS population, ContryCode FROM table GROUP BY CountryCode";
$result = mysql_query($upit);
while ($data = mysql_fetch_object($result)) {
    // $data->cities is the number of cities and $data->population the sum of people and $data->CountryCode the country code
}

Answer 5

计算国家/地区代码中的城市数量

$upit = "SELECT COUNT(DISTINCT CountryCode) FROM table_name
$num_rows = mysql_num_rows($upit);
echo "$num_rows Rows\n";

总结国家代码中所有城市的人口

请参阅@Mark Ba​​ker答案