Objective-C Json字符串到PHP数组

Question

我在这里做了接受的答案，但它对我不起作用。 我得到NULL 。

我从一个数组生成JSON：

    NSError* error;
    NSData *result =[NSJSONSerialization dataWithJSONObject:self.fileNamesListForUpload options:0 error:&error];
    NSString *displayJson = [[NSString alloc] initWithData:result
                                             encoding:NSUTF8StringEncoding];
     NSLog(@"json result %@",displayJson);

这打印["sample.pdf","sample-1.pdf"]然后我使用以下命令发布字符串

curl -F“nameList = [”sample.pdf“，”sample-1.pdf“]”url

在我的PHP代码中;

//get json string
    $jsonString = $_POST["nameList"];
    var_dump($_POST["nameList"]);
    $arrayOfNames=json_decode($jsonString,true);
    var_dump($arrayOfNames);
    echo "ArrayOfNames: ",$arrayOfNames,"\n";

结果是;

string(25) "[sample.pdf,sample-1.pdf]"
NULL
ArrayOfNames:

或者如果我添加引号''我得到;

string(27) "'[sample.pdf,sample-1.pdf]'"
NULL

当我使用_POST时，为什么“”被解雇？ [sample.pdf,sample-1.pdf]我发帖["sample.pdf","sample-1.pdf"] ？

如何解析json字符串并将其放入数组？

Answer 1

如果您发送请求为curl -F "nameList=["sample.pdf","sample-1.pdf"]" url

var_dump($_POST["nameList"])将返回string(25) "[sample.pdf,sample-1.pdf]" 。

如果你发送curl -F 'nameList=["sample.pdf","sample-1.pdf"]' url

var_dump($_POST["nameList"])将返回string(33) "[\\"sample.pdf\\",\\"sample-1.pdf\\"]" 。

您可以使用第二个选项并从字符串中删除反斜杠。

<?php
    $jsonString = $_POST["nameList"];
    var_dump($jsonString);
    $jsonString = str_replace("\\", "", $jsonString);
    var_dump($jsonString);
    $arrayOfNames=json_decode($jsonString,true);
    var_dump($arrayOfNames);
?>

Objective-C方面：

NSData *jsonArray =[NSJSONSerialization dataWithJSONObject:@[@"sample.pdf", @"sample-1.pdf"] options:0 error:nil];
NSString *stringFromJsonArray = [[NSString alloc] initWithData:jsonArray encoding:NSUTF8StringEncoding];
NSLog(@"%@", stringFromJsonArray); //["sample.pdf","sample-1.pdf"]

NSString *requestString = [NSString stringWithFormat:@"nameList=%@", stringFromJsonArray];
NSLog(@"%@", requestString); //nameList=["sample.pdf","sample-1.pdf"]

NSURL *url = [NSURL URLWithString:@"http://127.0.0.1/t.php"];
NSMutableURLRequest *request = [[NSMutableURLRequest alloc] initWithURL:url cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:60.0];
[request setHTTPMethod:@"POST"];
[request setHTTPBody:[requestString dataUsingEncoding:NSUTF8StringEncoding]];
NSData *responseData = [NSURLConnection  sendSynchronousRequest:request returningResponse:nil error:nil];
NSString *responseString = [[NSString alloc] initWithBytes:responseData.bytes length:responseData.length encoding:NSUTF8StringEncoding];
NSLog(@"%@", responseString);
/*
string(33) "[\"sample.pdf\",\"sample-1.pdf\"]"
string(29) "["sample.pdf","sample-1.pdf"]"
array(2) {
  [0]=>
  string(10) "sample.pdf"
  [1]=>
  string(12) "sample-1.pdf"
} */

Answer 2

您忘记了对JSON字符串进行urlencode，导致$ _POST解压缩部分内容，您不希望如此。

我不知道如何在Obj-C中进行url编码，但在PHP中它是：

"nameList=" . urlencode($json_string);

那么$_POST["nameList"]应该包含字符串["sample.pdf", "sample.pdf"] ，你可以json_decode那个。

Answer 3

我最终收到_POST请求并使用它;

$handle = fopen('php://input','r');
$jsonInput = fgets($handle);
$decoded = json_decode($jsonInput,true);


sendResponse(200, json_encode($decoded));

在Objective-c部分

NSError* error;
    NSData *result =[NSJSONSerialization dataWithJSONObject:self.fileNamesListForUpload options:0 error:&error];
    NSString *displayJson = [[NSString alloc] initWithData:result
                                             encoding:NSUTF8StringEncoding];
    NSLog(@"json result %@",displayJson);


    if ([self.fileNamesListForUpload count]>=1) {
        //send file upload request here
        NSURL* url = [NSURL URLWithString:deleteExtraFilesIn];
        __weak ASIHTTPRequest *request = [ASIHTTPRequest requestWithURL:url];


        [request addRequestHeader:@"User-Agent" value:@"ASIHTTPRequest"];
        [request addRequestHeader:@"Content-Type" value:@"application/json"];
        [request appendPostData:[displayJson  dataUsingEncoding:NSUTF8StringEncoding]];


        [request setCompletionBlock:^
         {
            if (request.responseStatusCode == 200) {

             //succesfully inserted row
                 NSError* error;
                 NSString *responseString = [request responseString];
                 NSDictionary* json =     [NSJSONSerialization JSONObjectWithData: [responseString dataUsingEncoding:NSUTF8StringEncoding]
                                                                          options: NSJSONReadingMutableContainers
                                                                            error: &error];

                 NSLog(@"recieved dict %@",json);


             }
}];

        [request setFailedBlock:^
         {
             //NEED RETURN FALSE
             //hide progress hud
         }];

        //start sync
        [request setDelegate:self];
        [request startAsynchronous];
    }