要使用apache httpclient，必须在远程http服务器上安装什么

Question

在一个项目中，我们使用apache httpclient，并且使用它时也没有例外。 但是问题是，我们无法在远程http服务器或任何其他位置上找到文件。

我们在线阅读了应该安装jakarta文件上传的信息，并且这样做了，但是现在我们陷入了困境。 由于没有文件上传到服务器，或者我们找不到它们。

有人吗

public class HttpServerHandler {

/**
 * A generic method to execute any type of Http Request and constructs a response object
 * @param requestBase the request that needs to be exeuted
 * @return server response as <code>String</code>
 */
private static String executeRequest(HttpRequestBase requestBase){
    String responseString = "" ;

    InputStream responseStream = null ;
    HttpClient client = new DefaultHttpClient () ;

    try{

        HttpResponse response = client.execute(requestBase);

        // get response of the server
        if (response != null){
            HttpEntity responseEntity = response.getEntity() ;

            if (responseEntity != null){
                responseStream = responseEntity.getContent();
                if (responseStream != null){
                    BufferedReader br = new BufferedReader (new InputStreamReader (responseStream)) ;
                    String responseLine = br.readLine() ;
                    String tempResponseString = "" ;
                    while (responseLine != null){
                        tempResponseString = tempResponseString + responseLine + System.getProperty("line.separator") ;
                        responseLine = br.readLine() ;
                    }
                    br.close() ;
                    if (tempResponseString.length() > 0){
                        responseString = tempResponseString ;
                    }
                }
            }
        }


    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IllegalStateException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }finally{
        if (responseStream != null){
            try {
                responseStream.close() ;
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    }
    client.getConnectionManager().shutdown() ;

    return responseString ;
}

/**
 * Method that builds the multi-part form data request
 * @param urlString the urlString to which the file needs to be uploaded
 * @param file the actual file instance that needs to be uploaded
 * @param fileName name of the file, just to show how to add the usual form parameters
 * @param fileDescription some description for the file, just to show how to add the usual form parameters
 * @return server response as <code>String</code>
 */
public String executeMultiPartRequest(String urlString, File file, String fileName, String fileDescription) {

    HttpPost postRequest = new HttpPost (urlString) ;
    try{

        MultipartEntity multiPartEntity = new MultipartEntity () ;

        //The usual form parameters can be added this way
        multiPartEntity.addPart("fileDescription", new StringBody(fileDescription != null ? fileDescription : "")) ;
        multiPartEntity.addPart("fileName", new StringBody(fileName != null ? fileName : file.getName())) ;

        /*Need to construct a FileBody with the file that needs to be attached and specify the mime type of the file. Add the fileBody to the request as an another part.
        This part will be considered as file part and the rest of them as usual form-data parts*/
        FileBody fileBody = new FileBody(file, "application/octect-stream") ;
        multiPartEntity.addPart("attachment", fileBody) ;

        postRequest.setEntity(multiPartEntity) ;
    }catch (UnsupportedEncodingException ex){
        ex.printStackTrace() ;
    }

    return executeRequest (postRequest);

}
}

这是将文件上传到http服务器的代码。 该文件是通过表单上传并传递给此类的？ 当我们尝试上传时，我们会收到状态码301的响应。

我们真正想要做的是通过apache的httpclient将文件上传到远程httpserver

Answer 1

顾名思义，它是一个“ http”客户端。 这意味着它可以在线上使用HTTP协议。 只要您发送有效的http请求，您的服务器就不需要也不应该知道此处的客户端（甚至可以是可以使用http的浏览器）

您是否在谈论http客户端的依赖关系？

当您说看不到异常时，您是否正在处理它们（与空的catch块不同？）需要代码来查找和复制问题