MySQL中语法错误：AS语句

Question

当我删除AS子句时，此SQL查询可以很好地工作。

$query = "SELECT bd_brushname FROM tbl_brushdescription WHERE MATCH(bd_brushname, bd_brushdescription) AGAINST ('brushes' IN BOOLEAN MODE) AS rank";
    $sqlquery = mysql_query($query);
    if($sqlquery === FALSE){
        die(mysql_error()); 
    }

当我使用AS ，它说You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'AS rank' at line 1 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'AS rank' at line 1

有人可以告诉我为什么它不起作用吗？

Answer 1

别名应放在您选择的列上，以：

• 在您的输出上重命名它们
• order by或having子句的order by使用别名

资源

了解您的请求后，您在此处使用别名作为条件，这有什么意义？

你想做什么？

Answer 2

更改“ AS等级”的位置

$query = "SELECT bd_brushname AS rank FROM tbl_brushdescription WHERE MATCH(bd_brushname, bd_brushdescription) AGAINST ('brushes' IN BOOLEAN MODE)";
    $sqlquery = mysql_query($query);
    if($sqlquery === FALSE){
        die(mysql_error()); 
    }