加入后错误地旋转桌子？

Question

SELECT

  GROUP_CONCAT(if(meta_summary = 'content', content, NULL)) AS content, 
  GROUP_CONCAT(if(meta_summary = 'supplemental', content, NULL)) AS supplemental,
  GROUP_CONCAT(if(meta_summary = 'heading', content, NULL)) AS heading,

cms_pages.meta_filename as filename

FROM
cms_pages

INNER JOIN cms_collection

ON

cms_collection.collection_id LIKE CONCAT('%', cms_pages.page_id,  '/heading%' )
OR cms_collection.collection_id LIKE CONCAT('%', cms_pages.page_id,  '/content%' )
OR cms_collection.collection_id LIKE CONCAT('%', cms_pages.page_id,  '/supplemental%' )

INNER JOIN

cms_content ON cms_collection.collection_id = cms_content.collection_id

WHERE
site_id = 51

GROUP BY
cms_pages.page_id

在 GROUP BY 之前的架构：

Filename        Content

pageA           (Heading Content)
pageA           (Content)
pageA           (Supplemental Content)

所需的规则集：

Filename       Heading            Content          Supplemental
pageA          (Heading Content) (Content)         (Supp. Content)

我尝试阅读http://www.artfulsoftware.com/infotree/queries.php#78，但无法弄清楚为什么这对我不起作用-好像是错误地将行串联在一起。有些看起来好像他们错误地合并了另一页的内容。 可能是因为我所有的联接都需要对concat组执行子查询吗？

更新＃1：创建了一个sqlfiddle @ http://sqlfiddle.com/#!2/fe3e3/1 ，但实际上在这里有效。

a）我没有正确地创建它b）也许是NaviCat弄乱了结果，尽管我对此表示怀疑

更新＃2：找到了原因-这是因为我使用的LIKE（正确地）匹配了子字符串，所以'2 / content'将匹配'22 / content'，依此类推。

如何有效更改cms_collection上的INNER JOIN以进行完全匹配？

Answer 1

尝试从LIKE字符串匹配连接条件的开头删除通配符，如下所示：

SELECT
  GROUP_CONCAT(if(meta_summary = 'content', content, NULL)) AS content, 
  GROUP_CONCAT(if(meta_summary = 'supplemental', content, NULL)) AS supplemental,
  GROUP_CONCAT(if(meta_summary = 'heading', content, NULL)) AS heading,
  cms_pages.meta_filename as filename
FROM cms_pages
INNER JOIN cms_collection ON
  cms_collection.collection_id LIKE CONCAT(cms_pages.page_id, '/heading%')
  OR cms_collection.collection_id LIKE CONCAT(cms_pages.page_id, '/content%')
  OR cms_collection.collection_id LIKE CONCAT(cms_pages.page_id, '/supplemental%')
INNER JOIN
  cms_content ON cms_collection.collection_id = cms_content.collection_id
WHERE
  site_id = 53
GROUP BY
  cms_pages.page_id

SQLFiddle 在这里 。