繁体   English   中英

如何使用ScreenShot Qt / QML

[英]How to take ScreenShot Qt/QML

QtQuick1示例我无法在QtQuick2上运行它

screenCapture.hpp

#include <QObject>

class QString;
class QQuickView;

class screenCapture : public QObject
{
    Q_OBJECT
public:    
    explicit screenCapture(QQuickView *parent = 0);

public slots:
    void capture(QString const &path) const;

private:
    QQuickView *currentView_;    
};

screenCapture.cpp

#include <QPixmap>
#include <QQuickView>
#include <QString>

#include "screenCapture.hpp"

screenCapture::screenCapture(QQuickView *currentView) :
    QObject(0), currentView_(currentView)
{
}

void screenCapture::capture(QString const &path) const
{
    QPixmap::grabWidget(currentView_).save(path);
}

main.cpp中

#include <QGuiApplication>
#include <QQuickPaintedItem>
#include <QQuickView>
#include <QQmlContext>

#include "screenCapture.hpp"

int main(int argc, char *argv[])
{
    QGuiApplication app(argc, argv);

    qmlRegisterType<screenCapture>("Image", 1, 0, "ScreenCapture");
    qmlRegisterType<saveAbleImage>("Image", 1, 0, "SaveAbleImage");

    QQuickView view;
    view.setResizeMode(QQuickView::SizeRootObjectToView);
    view.setSource(QStringLiteral("/Users/Qt/program/experiment_apps_and_libs/funnyCamera/qml/funnyCamera/main.qml"));
    view.show();

    screenCapture screenClass(&view);
    view.rootContext()->setContextProperty("screenObject", &screenClass);

    return app.exec();
}

main.qml

import QtQuick 2.0

Rectangle{
    id : root
    width : 1024
    height : 768    

    MouseArea{
        anchors.fill: root

        onClicked: {          
            console.log("save image")
            screenObject.capture("Pictures/saveTest.jpg")
        }
    }
}

错误信息

不推荐使用QPixmap :: grabWidget,使用QWidget :: grab()代替QMetaObject :: invokeMethod:没有这样的方法QQuickView :: grab(QRect)

我找到了一个解决方案,非常简单,将功能“捕获”更改为

void screenCapture::capture(QString const &path) const
{
    QImage img = currentView_->grabWindow();
    img.save(path);
}

暂无
暂无

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM