将JSON转换为Java组件

Question

我有这个json对象

data = {    
    "amount": "70",
    "cardNumber": "4222222222222",
    "expiryDate": "1215",
    "currency": "Currency.ISK.alpha" 
}

我想将此json对象更改为Java组件，并使用Java调用各种Java函数。 我在将此json对象转换为Java组件时遇到问题。 我创建了以下两个Java类。

@JsonAutoDetect
public class Handpoint {
private String amount;
private String cardNumber;
private String expireDate;
private String currency;

public String getAmount() { return amount; }
public void setAmount(String amount) { this.amount = amount; }

public String getCardNumber() { return cardNumber; }
public void setCardNumber(String cardNumber) { this.cardNumber = cardNumber; }

public String getExpireDate() { return expireDate; }
public void setExpireDate(String expireDate) { this.expireDate = expireDate; }

public String getCurrency() { return currency; }
public void setCurrency(String currency) { this.currency = currency; }

}

和

public class HandpointService {
public void ProcessPerson(@Payload Handpoint handpoint) {
    String cardNumber = handpoint.getCardNumber();
    cardNumber.toString();
}
}

配置文件很简单

<flow name="json_to_java_componentFlow1" doc:name="json_to_java_componentFlow1">
    <http:inbound-endpoint exchange-pattern="request-response" host="localhost" port="8081"     path="json" doc:name="HTTP"/>
    <component class="is.threesixtyfive.example.HandpointService" doc:name="Java"/>
</flow>

运行此命令时，出现以下错误：

Message               : Failed to transform from "json" to 

"is.threesixtyfive.example.Handpoint"
Code                  : MULE_ERROR-109
--------------------------------------------------------------------------------
Exception stack is:
1. Unrecognized field "expiryDate" (Class is.threesixtyfive.example.Handpoint), not marked as ignorable
 at [Source: java.io.InputStreamReader@26940a2e; line: 1, column: 98] (through reference chain: is.threesixtyfive.example.Handpoint["expiryDate"]) (org.codehaus.jackson.map.exc.UnrecognizedPropertyException)
  org.codehaus.jackson.map.exc.UnrecognizedPropertyException:53 (null)
2. Failed to transform from "json" to "is.threesixtyfive.example.Handpoint" (org.mule.api.transformer.TransformerException)
  org.mule.module.json.transformers.JsonToObject:136 (http://www.mulesoft.org/docs/site/current3/apidocs/org/mule/api/transformer/TransformerException.html)
--------------------------------------------------------------------------------
Root Exception stack trace:
org.codehaus.jackson.map.exc.UnrecognizedPropertyException: Unrecognized field "expiryDate" (Class is.threesixtyfive.example.Handpoint), not marked as ignorable
 at [Source: java.io.InputStreamReader@26940a2e; line: 1, column: 98] (through reference chain: is.threesixtyfive.example.Handpoint["expiryDate"])
    at org.codehaus.jackson.map.exc.UnrecognizedPropertyException.from(UnrecognizedPropertyException.java:53)
    at org.codehaus.jackson.map.deser.StdDeserializationContext.unknownFieldException(StdDeserializationContext.java:267)
    at org.codehaus.jackson.map.deser.std.StdDeserializer.reportUnknownProperty(StdDeserializer.java:673)
    + 3 more (set debug level logging or '-Dmule.verbose.exceptions=true' for everything)
********************************************************************************

任何帮助，将不胜感激

Answer 1

JSON和POJO之间的字段名称不同。
在JSON中： expiryDate
在POJO中： expireDate

Answer 2

问题来自于以下事实：

• 入站HTTP端点是request-response因此它将返回响应给调用者，
• component方法没有返回值。

Mule使用组件之后的当前消息有效负载（可能是消耗的输入流）来为入站终结点创建响应并失败。

如果我添加：

<set-payload value="foo" />

组件之后，错误将清除（HTTP客户端收到“ foo”）。

Answer 3

我认为，做到这一点的一种方法是首先处理转换部分，方法是使用JSON到Object的转换器并将其加载到映射引用，然后使用Java Component并将HandpointService类加载并使其可调用，这样您就可以拥有一个入口你上课。