子查询从一个查询中的两个表中选择多个COUNT

Question

我正在努力寻找我写过的最复杂的SQL查询！

数据库结构 ：

frog_shared.staff
`ID`, `Firstname`, `Surname`

frog_observations.observations
`ID`, `Teacher_ID`, `Type`, `Main_Positive_Aspect`, `Main_Development_Aspect`, `Grade_for_Behaviour`, `Grade_for_Attainment`, `Grade_for_Teaching`

frog_observations.aspects
`ID`, `Observation_ID`, `Label_ID`, `Type`

frog_observations.aspect_labels
`ID`, `Title`

样本数据 ：

Member of staff:
`12345`, `Duncan`, `Wraight`

Observation:
`9888`, `12345`, `Formal`, `5`, `7`, `1`, `1`, `1`

Aspects:
`101`, `9888`, `2`, `P`

Aspect labels:
`2`, `Questioning`

我想要实现的目标 ：

我想在特定的观察方面列出我们最好的老师名单。 例如，我想看看我的前五名教师的“提问”。

最重要的是，我想在某种程度上过滤数据：

• 应计算正式（ Type=Formal ）和共享最佳实践（ Type=SBP ）观察的方面
• 正式观察的方面只应计算，如果该观察的评分最高为2（不高，即不能有两个等级2和1，3），但分享最佳实践观察的等级均为0
• 记录在观察表中的主要积极方面应在计数中加权
• 对于正式观察，主要的积极方面应加权为正常方面的3 *
• 为了分享最佳实践观察，主要的积极方面应该加权为正常方面的2倍

我的尝试 ：

该声明按其等级过滤观察结果，但不包括任何主要的积极方面（它们未包含在原始系统中）

SELECT
  CONCAT(s.Firstname, " ", s.Surname) AS `Teacher`,
  COUNT( * ) AS Total,
  GREATEST(o.`Achievement_Grade`, o.`Behaviour_Grade`, o.`Teaching_Grade`) AS `Worst Grade`
FROM frog_observations.observations o
  INNER JOIN frog_shared.staff s ON o.Teacher_ID = s.ID
  INNER JOIN frog_observations.aspects a ON o.ID = a.Observation_ID
WHERE a.Aspect_ID =  4
  AND ( GREATEST(o.`Achievement_Grade`, o.`Behaviour_Grade`, o.`Teaching_Grade`) BETWEEN 1 AND 2 ) AND o.Datetime > '2011-09-01'
  AND a.Type =  'P'
GROUP BY s.ID
ORDER BY `Total` DESC 
LIMIT 5

现在我想做的方式是这样的：

SELECT
  CONCAT(s.Firstname, " ", s.Surname) AS `Teacher`,
  COUNT(mp.*) AS `Number of Appraisal Main Positives`,
  COUNT(sp.*) AS `Number of SBP Main Positives`,
  COUNT(a.*) AS `Number of Other Positives`,
  SUM(`Number of Appraisal Main Positives` + `Number of SBP Main Positives` `Number of Other Positives`) AS `Total`
FROM
  `frog_observations`.`observations` o,
  ( `frog_observations`.`observations` WHERE `Type` = 'Formal') AS mp,
  ( `frog_observations`.`observations` WHERE `Type` = 'SBP') AS sp
INNER JOIN
  `frog_observations`.`aspects` a ON a.Observation_ID = o.ID
GROUP BY s.ID

不幸的是，除了知道我想要的标题（即number of appraisal main positives number of sharing best practice positives number of standard positives和weighted total ）之外，我不知道如何编写我认为将是子查询的所有内容来自单一陈述的这些信息。

任何指导赞赏。

---

编辑：示例输入/输出

输入用户想要查看方面Questioning前5名员工

进程 - Aspect Questioning在aspect_labels表中具有ID 4 。 - 然后，系统应该为每个工作人员计算他们所拥有的observations ， Main_Positive_Aspect设置为4 。 其中一些观察结果将是正式Type ，一些将属于SBP Type 。 - 系统还应计算Aspect_ID为4每个工作人员的aspects表中的行数。

产量

键：

• FMP = observations表中Type为Formal的行数; GREATEST(Achievement_Grade, Behaviour_Grade, Teaching_Grade) BETWEEN 1 AND 2 ; 并且Main_Positive_Aspect为4 （即在aspects_label表中Questioning ）
• SMP = observations表中的行数，其中Type为SBP且Main_Positive_Aspect为4
• 其他 = aspects表中的行数，其中Aspect_ID为每个员工成员4 （通过o.Observation_ID - > o.Staff_ID链接）
• Points =每个FMP的加权总数 - 每个FMP值3个点，每个SMP值2个点，每个其他值1个。然后按此列查询查询， DESC 。

示例输出：

-------------------------------------------------------------
|       Staff Name      FMP     SMP     Other       Points  |
|------------------------------------------------------------
|       D Wraight       2       1       4           12      |
|       A Nother        3       0       0           9       |
|       J Bloggs        0       4       1           9       |
|       J Arthur        1       1       1           6       |
|       M Turner        0       1       0           2       |
-------------------------------------------------------------

---

以下是单独编写的查询，这些查询适用于我的数据库。 基本上我需要将这些合并为一个查询。 如果可能的话！

#=======#
#  FMP  #
#=======#

SELECT
  CONCAT(s.Firstname, " ", s.Surname) AS `Teacher`,
  COUNT( * ) AS `FMP`
FROM frog_observations.observations o
  INNER JOIN frog_shared.staff s ON o.Teacher_ID = s.ID
WHERE o.Main_Positive  =  4
  AND o.Type = 'F'
  AND ( GREATEST(o.`Achievement_Grade`, o.`Behaviour_Grade`, o.`Teaching_Grade`) BETWEEN 1 AND 2 )
GROUP BY s.ID

#=======#
#  SMP  #
#=======#

SELECT
  CONCAT(s.Firstname, " ", s.Surname) AS `Teacher`,
  COUNT( * ) AS `SMP`
FROM frog_observations.observations o
  INNER JOIN frog_shared.staff s ON o.Teacher_ID = s.ID
WHERE o.Main_Positive  =  4
  AND o.Type = 'S'
GROUP BY s.ID

#=========#
#  Other  #
#=========#

SELECT
  CONCAT(s.Firstname, " ", s.Surname) AS `Teacher`,
  COUNT( * ) AS `Other`
FROM observations o
  INNER JOIN frog_shared.staff s ON o.Teacher_ID = s.ID
  INNER JOIN aspects a ON o.ID = a.Observation_ID
WHERE a.Aspect_ID = 4
  AND a.Type = 'P'
GROUP BY s.ID

Answer 1

像这样的东西可以用于初始切割......

SELECT
  CONCAT(s.Firstname, " ", s.Surname) AS Teacher,
  sum(Case when `Type` = 'Formal' then 1 else 0 end) AS `Number of Appraisal Main Positives`,
  sum(Case when `Type` = 'SBP' then 1 else 0 end)  AS `Number of SBP Main Positives`,
  coalesce(OtherPositives,0) AS `Number of Other Positives`,
  sum(Case when `Type` in ( 'Formal' ,'SBP') then 1 else 0 end) + coalesce(OtherPositives,0)  AS `Total`
FROM observations o
INNER JOIN staff s ON o.Teacher_ID = s.ID
LEFT JOIN (select Observation_ID, count(*) as OtherPositives) from aspects where Label_ID=4 group by Observation_ID) a ON a.Observation_ID = o.ID
WHERE Main_Positive =4
GROUP BY s.ID