[英]SQL move row from one table to another with unmatched columns
我找到了很多关于如何插入使用select然后删除的例子,
我希望将数据从一个表移动到另一个表,例如,列不匹配
table1( id
, location
, lat
, lon
, date_added
)
table2( id
, location
, lat
, lon
, date_added
, requested
)
本质上我想从table1向table2插入一行,并将$ _SESSION ['user_name']添加到请求的字段,然后从第一个表中删除原始行。
我尝试了一些不同的东西
$sql = "START TRANSACTION;
INSERT INTO bia_signs_pending (SELECT * FROM bia_signs WHERE id = ".$_GET['sign_id'].');
DELETE FROM bia_signs WHERE id = ' .$_GET['sign_id'].';
UPDATE bia_signs_pending SET requested=' .$_SESSION['user']['email'].
'WHERE id = '.$_GET['sign_id'].';
COMMIT;';
//这个因为列不匹配而中断
有什么建议么?
您可以将INSERT
与列名一起使用
INSERT INTO TABLE2 (id, location, lat, lon, date_added)
SELECT id, location, lat, lon, date_added
FROM table1
WHERE ...
并且您可以将常量添加到INSERT
INSERT INTO TABLE2 (id, location, lat, lon, date_added, requested)
SELECT id, location, lat, lon, date_added, 'Jonny'
FROM table1
WHERE ...
只需更换插页即可
INSERT INTO bia_signs_pending (SELECT FROM bia_signs WHERE id = ".$_GET['sign_id'].');
至
INSERT INTO bia_signs_pending (id, location, lat, lon, date_added) VALUES (SELECT * FROM bia_signs WHERE id = '".$_GET['sign_id'].');
更改INSERT语句,添加您选择的字段列表:
INSERT INTO bia_signs_pending (id, location, lat, lon, date_added)
SELECT * FROM bia_signs WHERE id = '{$_GET['sign_id']}';
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