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[英]How to get a list of IDs from a parameter which sometimes includes the IDs already, but sometimes include another sql query
[英]How to reverse the table that comes from SQL query which already includes ORDER BY
这是我的查询:
SELECT TOP 8 id, rssi1, date
FROM history
WHERE (siteName = 'CCL03412')
ORDER BY id DESC
结果如下:
如何使用SQL根据日期(列2)反转此表?
您可以使用第一个查询来获取匹配的ID,并将其用作IN
子句的一部分:
SELECT id, rssi1, date
FROM history
WHERE id IN
(
SELECT TOP 8 id
FROM history
WHERE (siteName = 'CCL03412')
ORDER BY id DESC
)
ORDER BY date ASC
没有运行它,但我认为它应该运行良好
WITH cte AS
(
SELECT id, rssi1, date, RANK() OVER (ORDER BY ID DESC) AS Rank
FROM history
WHERE (siteName = 'CCL03412')
)
SELECT id, rssi1, date
FROM cte
WHERE Rank <= 8
ORDER BY Date DESC
请尝试以下方法:
select * from (SELECT TOP 8 id, rssi1, date
FROM history
WHERE (siteName = 'CCL03412')
ORDER BY id DESC ) aa order by aa.date DESC
我没有运行它,但我认为它将起作用。 执行并让我知道您是否遇到错误
选择ID,rssi1,日期,从(SELECT TOP 8 id,rssi1,date from history WHERE(siteName ='CCL03412')ORDER BY ID DESC)按日期排序;
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