SELECT行值WHERE MAX（）是GROUP BY查询中的列值

Question

我该如何选择？ 我可以创建用户定义的汇总函数吗

SELECT Max(A),(SELECT TOP 1 FROM TheGroup Where B=Max(A))从MyTable中SELECT Max(A),(SELECT TOP 1 FROM TheGroup Where B=Max(A))

MyTable如下所示

    A  B  C
--------------
    1  2  S
    3  4  S
    4  5  T
    6  7  T

我想要这样的查询

SELECT MAX(A),(B Where A=Max(A)),C FROM MYTable GROUP BY C

我期待如下结果

 MAX(A)  Condition    C
-----------------------
   3        4         S
   6        7         T

Answer 1

 SELECT A,B,C FROM
     (SELECT *, ROW_NUMBER() OVER (PARTITION BY C ORDER BY A DESC) RN FROM MyTable)
 WHERE RN = 1

（此查询始终每个C值仅返回一行）

要么

WITH CTE_Group AS 
(
    SELECT C, MAX(A) AS MaxA
    FROM MyTable
    GROUP BY C
)
SELECT g.MaxA, t.B, g.C
FROM MyTable t
INNER JOIN CTE_Group g ON t.A = g.MaxA AND t.C = g.C

（如果有多个行具有相同的Max（A）值-此查询将返回所有这些行）

Answer 2

SELECT Max(A)
FROM MyTable
Where B=(SELECT Max(A) FROM MyTable) 

更新：

SELECT *
FROM MyTable
Where B=(SELECT Max(A) FROM MyTable) 

更新2：

SELECT DISTINCT A, B
FROM MyTable
Where A=(SELECT Max(A) FROM MyTable GROUP BY C) 

更新3：

好的，我想我知道您现在要寻找的是什么。

SELECT *
FROM MyTable
Where A in (SELECT Max(A) FROM MyTable GROUP BY C) 

Answer 3

SELECT t1.*
FROM YourTable t1 
Left Outer Join YourTable t2 on t1.C=t2.C AND t1.A < t2.A
WHERE t2.A is null

Answer 4

WITH
  cte AS
(
  SELECT 
    ROW_NUMBER() OVER (ORDER BY cola desc) AS Rno,
    *
  FROM
    tbl
)
SELECT top 1
cola,colb
FROM
  cte
order by Rno

然后尝试：

    WITH
  cte AS
(
  SELECT 
    ROW_NUMBER() OVER (PARTITION BY col3 ORDER BY col1 desc) AS Rno,
    *
  FROM
    tbl

)
SELECT 
col1,col2,col3
FROM
  cte
WHERE Rno=1

Answer 5

这个怎么样：

    SELECT *
    FROM MyTable    
    WHERE A IN (SELECT MAX(A) FROM MyTable GROUP BY C)

Answer 6

尝试以下查询：

SELECT TABLE1.A , TABLE2.B , TABLE1.C
FROM 
(
    SELECT MAX(A) AS A,C 
    FROM MYTable 
    GROUP BY C
) AS TABLE1 
INNER JOIN
(
SELECT *
FROM MYTable
) AS TABLE2 ON TABLE1.A = TABLE2.A

SQLFIDDLE

您可以通过简单的连接查询来做到这一点。 连接查询总是比输入查询运行得更快。 连接查询在执行查询时仅运行一次。 我们可以使用IN查询来归档相同的结果。