[英]How to parse or split URL Address in Java?
如果我有 url 地址。
https://graph.facebook.com/me/home?limit=25&since=1374196005
我可以获取(或拆分)参数(避免硬编码)吗?
像这样
https /// graph.facebook.com /// me/home /// {limit=25, sincse=1374196005}
使用 Android 的Uri
类。 http://developer.android.com/reference/android/net/Uri.html
Uri uri = Uri.parse("https://graph.facebook.com/me/home?limit=25&since=1374196005");
String protocol = uri.getScheme();
String server = uri.getAuthority();
String path = uri.getPath();
Set<String> args = uri.getQueryParameterNames();
String limit = uri.getQueryParameter("limit");
对于纯 Java ,我认为这段代码应该可以工作:
import java.net.URL;
import java.net.URLDecoder;
import java.util.HashMap;
import java.util.Map;
public class UrlTest {
public static void main(String[] args) {
try {
String s = "https://graph.facebook.com/me/home?limit=25&since=1374196005";
URL url = new URL(s);
String query = url.getQuery();
Map<String, String> data = new HashMap<String, String>();
for (String q : query.split("&")) {
String[] qa = q.split("=");
String name = URLDecoder.decode(qa[0]);
String value = "";
if (qa.length == 2) {
value = URLDecoder.decode(qa[1]);
}
data.put(name, value);
}
System.out.println(data);
} catch (Exception e) {
e.printStackTrace();
}
}
}
kotlin
https://graph.facebook.com/me/home?limit=25&since=1374196005
import java.net.URI
import android.net.Uri
val uri = URI(viewEvent.qr)
val guid = Uri.parse(uri.fragment).getQueryParameter("c")
内置java.net.URL
应该服务。
URL url = new URL("https://graph.facebook.com/me/home?limit=25&since=1374196005");
String[] parts = {
url.getProtocol(),
url.getUserInfo(),
url.getHost(),
url.getPort(),
url.getPath(),
url.getQuery(),
url.getRef()
};
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