MySQL从一个表的列中选择一些值（不是所有值），并根据所选值在其他表中求和值

Question

第一个表（名为18_8_ChartOfAccounts ），帐号如此

AccountNumber | VatReturnRowNumberForDebitTurnover
--------------------------------------------------
 1            |    not_blank
 2            |
 3            |    not_blank

第二个表（名为2_1_journal ）就像这样

Amount | DebitAccount
----------------------
5     |  1
80    |  2
3     |  3
4     |  1
20    |  3

试图获得以下内容：如果VatReturnRowNumberForDebitTurnover不为空/非空白， DebitAccount与（等于） AccountNumber相同的Amount 。

或者想得到这样的输出：

Account number | Total
---------------------------
1              | 9 (5+4)
3              | 23 (20+3)

不需要为帐户2回显Total，因为对于帐户2 VatReturnRowNumberForDebitTurnover为空/空

这个mysql查询从第一个表中选择所有 AccountNumber （ 18_8_ChartOfAccounts ）

SELECT a.AccountNumber, IFNULL( d.Amount, 0 ) AS Amount 
FROM 18_8_ChartOfAccounts AS a 
LEFT JOIN ( SELECT DebitAccount, SUM( Amount ) AS Amount 
FROM ( SELECT * FROM 2_1_journal) DATA 
GROUP BY DebitAccount ) 
d ON (a.AccountNumber = d.DebitAccount)

但需要选择只AccountNumber s其中VatReturnRowNumberForDebitTurnover不为空/空

试图修改mysql查询

SELECT a.AccountNumber, IFNULL( d.Amount, 0 ) AS Amount 
FROM 18_8_ChartOfAccounts AS a 

WHERE VatReturnRowNumberForDebitTurnover <> ''

LEFT JOIN ( SELECT DebitAccount, SUM( Amount ) AS Amount 
FROM ( SELECT * FROM 2_1_journal) DATA 
GROUP BY DebitAccount ) 
d ON (a.AccountNumber = d.DebitAccount)

获取Syntax error or access violation: ... near 'LEFT JOIN ( SELECT DebitAccount ....

然后更改FROM 18_8_ChartOfAccounts AS a WHERE VatReturnRowNumberForDebitTurnover <> ''

to FROM 18_8_ChartOfAccounts WHERE VatReturnRowNumberForDebitTurnover <> '' AS a并得到类似的错误。

然后改为这样的代码：

SELECT a.AccountNumber, IFNULL( d.Amount, 0 ) AS Amount 
FROM 18_8_ChartOfAccounts AS a 
LEFT JOIN ( SELECT DebitAccount, SUM( Amount ) AS Amount 
FROM ( SELECT * FROM 2_1_journal) DATA 
WHERE a.VatReturnRowNumberForDebitTurnover <> "" 
GROUP BY DebitAccount ) 
d ON (a.AccountNumber = d.DebitAccount)

并获取Unknown column 'a.VatReturnRowNumberForDebitTurnover'

2_1_journal表2_1_journal没有这样的专栏。 想用a.VatReturnRowNumberForDebitTurnover以同样的方式为a.AccountNumber （两列仅在18_8_ChartOfAccounts 。 a.AccountNumber工作， a.VatReturnRowNumberForDebitTurnover没有。

请，建议需要修改的内容

Answer 1

这应该工作;

SELECT AccountNumber, 
       CONCAT(SUM(Amount), ' (', GROUP_CONCAT(Amount SEPARATOR '+'), ')') Total
FROM 18_8_ChartOfAccounts
LEFT JOIN 2_1_journal
  ON AccountNumber = DebitAccount
WHERE VatReturnRowNumberForDebitTurnover IS NOT NULL
GROUP BY AccountNumber

一个要测试的SQLfiddle 。

当然，如果总和细节只是一个例子，你可以跳过GROUP_CONCAT()部分，然后使用......

SELECT AccountNumber, COALESCE(SUM(Amount), 0) Total
...

另一个SQLfiddle 。

Answer 2

只需使用此查询：

SELECT a.AccountNumber, SUM( b.Amount ) AS Amount
  FROM 18_8_ChartOfAccounts AS a 
     LEFT JOIN 2_1_journal AS b ON a.AccountNumber = b.DebitAccount
        WHERE a.VatReturnRowNumberForDebitTurnover IS NOT NULL
        GROUP BY b.DebitAccount;

Answer 3

select
ca.AccountNumber,
sum(j.Amount)
from
18_8_ChartOfAccounts ca
left join 2_1_journal j on ca.AccountNumber = j.DebitAccount
where 
ca.VatReturnRowNumberForDebitTurnover is not null
group by ca.AccountNumber

看到它在sqlfiddle中工作 。