postgres选择regexp_split_to_table生成的行的位置，其中union抛出错误

Question

我有一个表'my_table'，其中两列（c1，c2）以完全相同的格式保存数据'1,2,3,4; 5,6,7,8'我使用regexp_split_to_table将它们分成行，而我我试图选择非空行。

SELECT * from 
 (SELECT '1' as param1 ,'2' as param2, param3 FROM
  ((select regexp_split_to_table(my_table.c1, ';') as param3
   FROM  my_table)
 UNION
  (select regexp_split_to_table(my_table.c2, ';') as param3
   FROM  my_table)) AS a) as b

 where param3 is not null

运行此查询会出现以下错误：

set-valued function called in context that cannot accept a set

如果我删除联合并仅从其中一个列中选择，或者通过其他字段之一（param1 / param2）进行筛选，则查询可以正常工作。 我认为这可能是数据的问题所以我尝试从同一列中选择两次：

SELECT * from 
 (SELECT '1' as param1 ,'2' as param2, param3 FROM
  ((select regexp_split_to_table(my_table.c1, ';') as param3
   FROM  my_table)
 UNION
  (select regexp_split_to_table(my_table.c1, ';') as param3
   FROM  my_table)) AS a) as b

 where param3 is not null

但我仍然得到同样的错误。 有谁知道如何解决这个问题？ 谢谢！

Answer 1

我建议使用CTE而不是子查询并格式化您的查询。 这是我认为你需要的查询：

with cte1 as (
  select regexp_split_to_table(t.c1, ';') as param3
  from my_table as t
  union all
  select regexp_split_to_table(t.c2, ';') as param3
  from my_table as t
)
select '1' as param1 ,'2' as param2, c.param3
from cte1 as c
where c.param3 is not null

sql小提琴演示

注意：我不知道你的查询中是否需要重复，所以如果你不需要重复 - 请使用union而不是union all

更新

with cte1 as (
  select regexp_split_to_table(t.c1, ';') as param3
  from my_table as t
  union all
  select regexp_split_to_table(t.c2, ';') as param3
  from my_table as t
), cte2 as (
  select regexp_split_to_table(c.param3, ',') as param3
  from cte1 as c
  where c.param3 is not null and c.param3 <> ''
)
select *
from cte2 as c
where c.param3 is not null and c.param3 <> ''

sql小提琴演示

update2甚至可以用一个正则表达式完成

with cte1 as (
    select c1 as param3 from my_table
    union all
    select c2 as param3 from my_table
), cte2 as (
  select regexp_split_to_table(param3, '(;|,)') as param3
  from cte1
)
select '1' as param1 ,'2' as param2, c.param3
from cte2 as c
where nullif(c.param3, '') <> ''

sql小提琴演示