[英]Php Search Script only pick up the first word
作为问题,它只选择了我的product_name中以var_char(50)作为主键的第一个单词。
<?php
error_reporting(E_ALL);
ini_set('display_errors', '1');
$search_output = "";
if(isset($_POST['searchquery']) && $_POST['searchquery'] != ""){
$searchquery = $_POST['searchquery'];
if($_POST['filter1'] == "Whole Site"){
$sqlCommand = "SELECT * FROM products WHERE MATCH (product_name ,details,category,subcategory) AGAINST ('".$searchquery."' IN BOOLEAN MODE)";
}
require_once("storescripts/connect_to_mysqli.php");
$query = mysqli_query($myConnection,$sqlCommand) or die(mysqli_error($myConnection));
$count = mysqli_num_rows($query);
if($count > 1){
$search_output .= "<hr />$count results for <strong>$searchquery</strong><hr />$sqlCommand<hr />";
while($row = mysqli_fetch_array($query)){
$id=$row["id"];
$product_name = $row["product_name"];
$details= $row["details"];
$category=$row["category"];
$subcategory=$row["subcategory"];
$search_output .= "ID: $id <br/> Name: $product_name -<br/>$details<br />$category<br/>$subcategory<br/>
<a href='product.php?id=$id'>link</a><br/>
";
} // close while
} else {
$search_output = "<hr />0 results for <strong>$searchquery</strong><hr />$sqlCommand";
}
}
?>
<html>
<head>
</head>
<body>
<h2>Search the Exercise Tables</h2>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
Search For:
<input name="searchquery" type="text" size="44" maxlength="88">
Within:
<select name="filter1">
<option value="Whole Site">Whole Site</option>
</select>
<input name="myBtn" type="submit">
<br />
</form>
<div>
<?php echo $search_output; ?>
</div>
</body>
这是因为它是主键吗? 它实际上并没有为细节工作,它实际上很奇怪,没有为大多数单词工作,而是为某些单词工作..我完全感到困惑..它没有任何意义
<?php
error_reporting(E_ALL);
ini_set('display_errors', '1');
require_once("storescripts/connect_to_mysqli.php");
$search_output = "";
if(isset($_POST['searchquery']) && $_POST['searchquery'] != ""){
$searchquery = $_POST['searchquery'];
if($_POST['filter1'] == "Whole Site"){
$sqlCommand = sprintf("SELECT * FROM products WHERE product_name LIKE '%s%%'",
mysqli_real_escape_string($myConnection, $searchquery));
}
$query = mysqli_query($myConnection,$sqlCommand) or die(mysqli_error($myConnection));
$count = mysqli_num_rows($query);
if($count > 1){
$search_output .= "<hr />$count results for <strong>$searchquery</strong><hr />$sqlCommand<hr />";
while($row = mysqli_fetch_array($query)){
$id=$row["id"];
$product_name = $row["product_name"];
$details= $row["details"];
$category=$row["category"];
$subcategory=$row["subcategory"];
$search_output .= "ID: $id <br/> Name: $product_name -<br/>$details<br />$category<br/>$subcategory<br/>
<a href='product.php?id=$id'>link</a><br/>
";
} // close while
} else {
$search_output = "<hr />0 results for <strong>$searchquery</strong><hr />$sqlCommand";
}
}
?>
<html>
<head>
</head>
<body>
<h2>Search the Exercise Tables</h2>
<form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post">
Search For:
<input name="searchquery" type="text" size="44" maxlength="88">
Within:
<select name="filter1">
<option value="Whole Site">Whole Site</option>
</select>
<input name="myBtn" type="submit">
<br />
</form>
<div>
<?php echo $search_output; ?>
</div>
</body>
</html>
我也尝试了上面的代码,并缩小到product_name,它仍然没有显示,例如,如果我输入“ fish”,那么我将这个product_name输入为“ omega fish”,则没有显示任何内容,如果我输入了“ omega”,那么它作品
我已经放弃了这一点,并尝试使用LIKE函数,它似乎更好,但仍然很有趣。请对感兴趣的人参考此链接
谢谢
请参考用于MySQL数据库的PHP搜索脚本,只有3个字母有效,我认为这是一个类似的问题,只需将$ count> 1更改为$ count = 0或$ count> = 1
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.