Android在活动之间切换

Question

我要做的是一个主屏幕，停留5秒钟，然后进入活动1.当我点击activity1中的按钮导致我活动2.我已经尝试了很多次点击按钮，但没有切换发生。 homescreen（5秒）= Main_Activity Activity1 = selectpets.java Activity2 = fishtank.java

onclick听众似乎问题我不知道它有什么问题

     Main Activity Code
package com.set.petshome;
import android.os.Bundle;
import android.os.Handler;
import android.app.Activity;
import android.content.Intent;
import android.view.Menu;
import android.view.View;
import android.widget.Button;

public class MainActivity extends Activity {
    Button fButton;
    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);
        //Delay Code after 5 seconds
        new Handler().postDelayed(new Runnable() {
            @Override
            public void run() {
                setContentView(R.layout.selectscreen); //where <next> is you target      activity :)
                }
            }, 5000);   
    }
//Delay End
    @Override
    public boolean onCreateOptionsMenu(Menu menu) {
        // Inflate the menu; this adds items to the action bar if it is present.
        getMenuInflater().inflate(R.menu.main, menu);
        return true;
    }
}

现在是Selectpets代码

package com.set.petshome;

import android.app.Activity;
import android.content.*;
import android.os.Bundle;
import android.view.*;
import android.widget.Button;
public class SelectPetsScreen extends Activity  {
    Button fButton;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.selectscreen);

      //Button Fishtank Listener Start

        fButton = (Button) findViewById(R.id.button1);

          //Listening to button event
           fButton.setOnClickListener(new View.OnClickListener() {

                public void onClick(View arg0) {
                    //Starting a new Intent
                    Intent nextScreen = new Intent(getApplicationContext(),  fishtank.class);
                    startActivity(nextScreen);

                }
            });     
        //Button Fishtank Listener End

    }
   }

Fishtank类代码

package com.set.petshome;

import android.app.Activity;
import android.content.Intent;
import android.os.Bundle;
import android.view.Menu;
import android.view.View;
import android.widget.Button;

    public class fishtank extends Activity {
        @Override
        public void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.ftank);



        }

    }

顺便说一下，点击后应用程序中的错误没有切换
非常感谢你

Answer 1

在这里，您永远不会切换到下一个Activity ，只需更改当前Activity的layout

 new Handler().postDelayed(new Runnable() {
            @Override
            public void run() {
                setContentView(R.layout.selectscreen); //where <next> is you target      activity :)
                }
            }, 5000);  

而不是setContentView()你需要使用一个Intent

Intent i = new Intent(MainActivity.this, SelectPetsScreen.this);
startActivity(i);

由于您实际上没有进入下一个Activity （java文件onClick()因此未设置onClick() 。

编辑

这就是你在做什么

public class MainActivity extends Activity {
Button fButton;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    //Delay Code after 5 seconds
    new Handler().postDelayed(new Runnable() {
        @Override
        public void run() {
            setContentView(R.layout.selectscreen); //where <next> is you target      activity :)
            }
        }, 5000);   
}

这就是你应该做的。 注意run()函数的区别

public class MainActivity extends Activity {
Button fButton;
@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);
    //Delay Code after 5 seconds
    new Handler().postDelayed(new Runnable() {
        @Override
        public void run() {
            Intent i = new Intent(MainActivity.this, SelectPetsScreen.this);
            startActivity(i);
            }
        }, 5000);   
}

Answer 2

避免这样做。

 setContentView(R.layout.activity_main);
        //Delay Code after 5 seconds
        new Handler().postDelayed(new Runnable() {
            @Override
            public void run() {
                setContentView(R.layout.selectscreen); //where <next> is you target      activity :)
                }
            }, 5000);   

Google为您提供了切换活动的Intent机制

即使用

startActivity(new Intent(this, yourSecondActivity.class));

代替

setContentView(R.layout.selectscreen);

代码的其余部分必须正常工作。

Answer 3

如果你只想使用firts Activity一次，你可以使用finish() 。

mHandler.postDelayed(new Runnable() {
    @Override
    public void run() {

 startActivity(new Intent().setClass(MainActivity.this, SelectPetsScreen .class).setData(getIntent().getData()));
        finish();
    }
}, 5000);

确保在Manifest.xml中定义了第二个Activity：

<activity android:name="x.x.SelectPetsScreen"
        android:theme="@style/NoTitle"
        android:screenOrientation="nosensor"
        android:launchMode="singleTask">
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />
        </intent-filter>
    </activity>

Answer 4

我能够在Maxim Shoustin和大家的帮助下解决它：将第二个Activity添加到Manifest.xml，这是SelectPetsScreen非常感谢你