[英]Scanner only accepting input once
最近,我一直在从事Noughts and Crosses游戏,但偶然发现了一个似乎无法解决的问题。
每当我第一次输入内容时,它都可以工作并打印出电路板,但是从那以后,它将停止检查并打印出电路板。
while(inf){
String temp = input.next();
if(playerTurn == 1){
if(amountP1 <= 3){
if(temp.equalsIgnoreCase("00")){
if(board[0][0] == 0){
board[0][0] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("01")){
if(board[0][1] == 0){
board[0][1] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("02")){
if(board[0][2] == 0){
board[0][2] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("10")){
if(board[1][0] == 0){
board[1][0] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("11")){
if(board[1][1] == 0){
board[1][1] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("12")){
if(board[1][2] == 0){
board[1][2] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("20")){
if(board[2][0] == 0){
board[2][0] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("21")){
if(board[2][1] == 0){
board[2][1] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("22")){
if(board[2][2] == 0){
board[2][2] = 1;
showBoard(board);
playerTurn = 2;
amountP1++;
}
else{
System.out.println("This space is already occupied!");
}
}
}
else if(playerTurn == 2){
if(amountP2 <= 3){
if(temp.equalsIgnoreCase("00")){
if(board[0][0] == 0){
board[0][0] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("01")){
if(board[0][1] == 0){
board[0][1] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("02")){
if(board[0][2] == 0){
board[0][2] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("10")){
if(board[1][0] == 0){
board[1][0] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("11")){
if(board[1][1] == 0){
board[1][1] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("12")){
if(board[1][2] == 0){
board[1][2] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("20")){
if(board[2][0] == 0){
board[2][0] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("21")){
if(board[2][1] == 0){
board[2][1] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
else if(temp.equalsIgnoreCase("22")){
if(board[2][2] == 0){
board[2][2] = 2;
showBoard(board);
playerTurn = 1;
amountP2++;
}
else{
System.out.println("This space is already occupied!");
}
}
}
}
}
}
这是印制电路板的方法:
public static void showBoard(int x[][]){
int rowNumber = 1;
for(int row = 0 ; row < x.length ; row++){
for(int column = 0 ; column < x[row].length ; column++){
if(x[row][column] == 0){
if(rowNumber <= 2){
System.out.print(" E");
rowNumber++;
}
else if(rowNumber == 3){
System.out.println(" E");
rowNumber = 1;
}
}
else if(x[row][column] == 1){
if(rowNumber <= 2){
System.out.print(" X");
rowNumber++;
}
else if(rowNumber == 3){
System.out.println(" X");
rowNumber = 1;
}
}
else if(x[row][column] == 2){
if(rowNumber <= 2){
System.out.print(" O");
rowNumber++;
}
else if(rowNumber == 3){
System.out.println(" O");
rowNumber = 1;
}
}
}
}
}
另外,我知道这段代码是一团糟,可能还有许多其他更有效的方式来执行此操作,但是由于我是一位相当新的程序员,因此我选择在此功能上选择功能而不是效率。
您的else if(playerTurn == 2)
行需要拉到与if(playerTurn == 1)
相同的级别:
if(playerTurn == 1){
if(amountP1 <= 3){
//...
}
else if(playerTurn == 2){
//...
}
}
应该成为
if(playerTurn == 1){
if(amountP1 <= 3){
//...
}
} else if(playerTurn == 2) {
//...
}
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