[英]MySQLI Inner Join 2 Tables
我在这里做错了什么。 我已经遵循了许多示例,但似乎无法使其正常工作。 我有2张桌子
表 => 用户
user_id
user_name
user_email
user_password
user_country
user_dobdate
user_company
user_code
user_status
user_type
表 => 应用程序
apply_id
apply_from
apply_leave_type
apply_priority
apply_start_date
apply_end_date
apply_halfday
apply_contact
apply_reason
apply_status
apply_comment
apply_dated
apply_action_date
SQLI查询
$query = $db->select("SELECT users.user_id, app.apply_from FROM users INNER JOIN applications ON users.user_id = app.apply_from WHERE users.user_code='1'");
$rows = $db->rows();
foreach ($rows as $apply){
$apply_id = $apply['apply_id'];
$apply_from = $apply['apply_from'];
错误信息
Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in xxxxxxxxxxxxxxx line 26
您的查询;
SELECT users.user_id, app.apply_from
FROM users
INNER JOIN applications
ON users.user_id = app.apply_from
WHERE users.user_code='1'
...为表application
使用别名app
,但不声明它。
INNER JOIN applications app
您错过了表applications
的别名作为app
in join
。 请尝试以下操作:
SELECT users.user_id,app.apply_from
FROM users
INNER JOIN applications app ON users.user_id = app.apply_from
WHERE users.user_code='1'
为applications
表添加缩写“app”:
SELECT
users.user_id,
app.apply_from
FROM
users
INNER JOIN
applications AS app
ON
users.user_id = app.apply_from
WHERE
users.user_code='1'
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.