RegExp查找标签和变量

Question

您能否更正我的RegExp使其正常工作？ 我需要检查我要替换的字符串是否没有被标签包围。

var re = new RegExp("<a\b[^>]*>"+variable+"<\/a>","gi");

Answer 1

您必须先捕获所有链接并自行替换它们：

var variable = "os";
var yourstring= "sdfsdlkjfsd <a href=blux> os</a> sdfsdflkjsdf os";

var re = new RegExp("(<a\\b[^>]*>(?:[^<]+|<(?!/a>))*</a>)|("+variable+")","gi");

function replacer(match, p1, p2){
    var replacement = "glups";
    return (p1)? p1 : replacement;
};
var result = yourstring.replace(re, replacer);
console.log(result);

图案细节：

(?:[^<]+|<(?!/a>))*描述之间的“a”的标签的内容的装置，以及

(?:          # open a non capturing group
    [^<]+    # all characters except < one or more times
  |          # OR
    <(?!/a>) # < not followed by "/a>"
)*           # close the non capturing group and repeat zero or more times

Answer 2

您需要将\\\\b的反斜杠加倍，以使其通过\\b到达正则表达式：

var re = new RegExp("<a\\b[^>]*>"+variable+"<\/a>","gi");