[英]How do I remove some of the square brackets that wrap a JSON array
我正在尝试锻炼如何格式化包裹我的JSON数组的括号。 我正在使用此代码从数据库中提取阵列数据。
$result = mysqli_query($con,"SELECT * FROM table");
$column = array();
while ($row = mysqli_fetch_array($result))
{
$column[] = array(array($row[0],$row[1],$row[2],$row[3],$row[4],$row[5]),$row[3],$row[2],$row[0]);
}
转换为JSON后,数组将以这种格式打印到屏幕上。 我需要保留第一个方括号,但需要将第二组方括号替换为(\\')。
var myVar = [
[["22","mike"," 151.1272","-33.9324","learning to fish","08\/14\/13"],"-33.93024"," 151.12896172","22"],
[["23","mike"," -2.09875","51.44501","learning french","08\/04\/13"],"51.44501"," -2.09775","23"],
[["24","mike"," -2.16375","51.44823019014051","Programming","08\/05\/13"],"51.451"," -2.1675","24"],
];
因此,Array应该看起来更像这样。
var myVar = [
['"22","mike"," 151.12","-33.934","learning to fish","08\/14\/13"',"-33.94"," 151.12","22"],
['"23","mike"," -2.095","51.41","learning french","08\/04\/13"',"51.41"," -2.095","23"],
['"24","mike"," -2.165","51.41","Programming","08\/05\/13"',"51.44851"," -2.1675","24"],
];
我需要这种格式的Array的原因是为了可以将数据传递到Google Maps函数中,该函数希望Array具有4列。
我已经计算出可以使用类似的功能移除支架,但是问题是它移除了所有支架,并且我需要外部支架。
$js_array = str_replace(array('[', ']'), '\'', htmlspecialchars(json_encode($column), ENT_NOQUOTES));
我如何保留外部支架并简单地卸下内部支架? 如果我没有提供足够的信息,或者我应该添加更多详细信息,请告诉我。
谢谢
首先如何按照需要的方式制作数组? 代替:
$column[] = array(
array(
$row[0],
$row[1],
$row[2],
$row[3],
$row[4],
$row[5]
),
$row[3],
$row[2],
$row[0]
);
做这个:
$column[] = array(
$row[0] . $row[1] . $row[2] . $row[3] . $row[4] . $row[5],
$row[3],
$row[2],
$row[0]
);
尝试
str_replace('[["','[\'"',$string);
以及如果括号在末尾也加倍(不在您的示例中)
str_replace('"]]','"\']',$string);
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