[英]'Greater than or equal' and 'less than or equal' CODEIGNITER
我必须查询具有>=
和=<
的where条件的东西,但是我没有运气。 这在CODEIGNITER中 。
这是mysql查询中的自然方法:
SELECT COUNT(payment.keyid) AS rec_count, `product_key`.`client_name`,
`product_key`.`contact_email`, `product_key`.`status`, `product_key`.`id`,
`payment`.`paymentdate`, (payment.id) as pid, `payment`.`subscription_type`
FROM (`product_key`)
LEFT OUTER JOIN `payment` ON `payment`.`keyid`=`product_key`.`id`
WHERE `payment`.`paymentdate` >= '2013-08-01'
AND `payment`.`paymentdate` =< '2013-08-31'
AND `status` = 'purchased'
GROUP BY `product_key`.`id`
ORDER BY `client_name` asc
这就是我所拥有的:
return $this->db
->select('COUNT(payment.keyid) AS rec_count')
->select('product_key.client_name, product_key.contact_email, product_key.status, product_key.id, payment.paymentdate, (payment.id) as pid,payment.subscription_type')
->from('product_key')
->where('payment.paymentdate >=', $month_start)
->where('payment.paymentdate =<', $month_end)
->where('status', 'purchased')
->join('payment', 'payment.keyid=product_key.id', 'left outer')
->order_by('client_name', "asc")
->group_by('product_key.id')
->get()
->result();
也许有人可以帮助我。 谢谢。
将=<
更改为<=
。
我也在phpmyadmin中测试了您当前的查询,因为我不敢相信它不会引发错误。 但是我的做到了。 因此,您的查询在phpmyadmin中不起作用。
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '=< ...' at line ...
尝试将=<
更改为<=
->where('payment.paymentdate >=', $month_start)
->where('payment.paymentdate <=', $month_end)
而且更好,但不是cumpolsury在where条件之前加入表。现在您的查询应该像
->select('COUNT(payment.keyid) AS rec_count')
->select('product_key.client_name, product_key.contact_email, product_key.status, product_key.id, payment.paymentdate, (payment.id) as pid,payment.subscription_type')
->from('product_key')
->join('payment', 'payment.keyid=product_key.id', 'left outer')
->where('payment.paymentdate >=', $month_start)
->where('payment.paymentdate <=', $month_end)
->where('status', 'purchased')
->order_by('client_name', "asc")
->group_by('product_key.id')
->get()
尝试:
$this->db
->select('COUNT(payment.keyid) AS rec_count, product_key.client_name, product_key.contact_email, product_key.status, product_key.id, payment.paymentdate, (payment.id) as pid, payment.subscription_type', false)
->from('product_key')
->join('payment', 'payment.keyid=product_key.id', 'LEFT OUTER')
->where('payment.paymentdate >=', '2013-08-01')
->where('payment.paymentdate =<', '2013-08-31')
->where('status', 'purchased')
->group_by('product_key.id')
->order_by('client_name', 'asc')
->get();
据我所知,你可以这样写
$this->db->select('COUNT(payment.keyid) AS rec_count, product_key.client_name, product_key.contact_email, product_key.status, product_key.id, payment.paymentdate, (payment.id) as pid, payment.subscription_type', false);
$this->db->where('payment.paymentdate >= "2013-08-01"');
$this->db->where('payment.paymentdate <= "2013-08-31"');
$this->db->where('status', 'purchased');
$this->db->group_by('product_key.id');
$this->db->order_by('client_name', 'asc');
$this->db->join('payment', 'payment.keyid=product_key.id', 'LEFT OUTER')
$this->db->get('product_key');
$this->db->where("DATE_FORMAT(ph_payment_date, '%d-%m-%Y') BETWEEN '$startdate' AND '$enddate'");
$this->db->where("DATE_FORMAT(ph_payment_date, '%d-%m-%Y') >= '$startdate'");
$this->db->where("DATE_FORMAT(ph_payment_date, '%d-%m-%Y') <= '$enddate'");
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