[英]Hibernate one to one mapping annotation insert exception (While inserting into transnational table, master table data should not change)
Oracle表DDL:
CREATE TABLE M_SERVICE
(
SERVICE_ID NUMBER (10) PRIMARY KEY,
SERVICE_NM VARCHAR2 (255),
ACTIVE_SW CHAR (1),
LST_UPDT_DT DATE,
LST_UPDT_BY VARCHAR2 (32)
)
CREATE TABLE T_JOB
(
JOB_ID NUMBER PRIMARY KEY,
JOB_NM VARCHAR2 (32),
JOB_DESC VARCHAR2 (2000),
SERVICE_ID NUMBER,
DUE_DT DATE,
LST_UPDT_DT DATE,
LST_UPDT_BY VARCHAR2 (32),
CONSTRAINT T_JOB_FK1 FOREIGN KEY
(SERVICE_ID)
REFERENCES M_SERVICE (SERVICE_ID)
)
M_SERVICE是一个主表。 T_JOB是一个事务表。 我的要求是,当我尝试在T_job表中插入时,不应在M_service表中插入/更新(所有service_Id在M_SERVICE中都可用)。 但是在选择时,我需要两个表数据。
实体:
@Entity
@Table(name = "M_SERVICE")
public class ServiceVO implements Serializable {
private static final long serialVersionUID = -2684205897352720653L;
@Id
@GeneratedValue(strategy = GenerationType.AUTO, generator = "SEQ_SERVICE_ID")
@SequenceGenerator(name = "SEQ_SERVICE_ID", sequenceName = "SEQ_SERVICE_ID")
@Column(name = "SERVICE_ID")
private Integer serviceId;
@Column(name = "SERVICE_NM")
private String serviceName;
@Column(name = "ACTIVE_SW")
private char activeSwitch;
@Column(name = "LST_UPDT_DT")
@Temporal(TemporalType.DATE)
private Date lastUpdatedDt;
@Column(name = "LST_UPDT_BY")
private String lastUpdatedBy;
//Getter & Setters.
}
@Entity
@Table(name = "T_JOB")
public class JobVO implements Serializable {
private static final long serialVersionUID = 7167763557817486917L;
@Id
@GeneratedValue(strategy = GenerationType.AUTO, generator = "SEQ_JOB_ID")
@SequenceGenerator(name = "SEQ_JOB_ID", sequenceName = "SEQ_JOB_ID")
@Column(name = "JOB_ID")
private Integer jobId;
@Column(name = "JOB_NM", nullable = false)
private String jobName;
@Column(name = "JOB_DESC")
private String jobDesc;
@OneToOne(cascade = CascadeType.ALL)
@JoinColumn(name = "SERVICE_ID", referencedColumnName = "SERVICE_ID", insertable = false, updatable = false)
private ServiceVO service;
@Column(name = "DUE_DT", nullable = false)
@Temporal(TemporalType.DATE)
private Date dueDate;
@Column(name = "LST_UPDT_DT", nullable = false)
@Temporal(TemporalType.DATE)
private Date lastUpdatedDt;
@Column(name = "LST_UPDT_BY", nullable = false)
private String lastUpdatedBy;
//Getter & Setters.
}
如果我打电话要求根据工作ID表示特定的工作详细信息,那么我可以像下面期望的那样获得信息,
this.sessionFactory.getCurrentSession().get(JobVO.class, id);
JobVO [jobId = 1,jobName = job name,jobDesc = desc,service = ServiceVO [serviceId = 2,serviceName = Tax Audit,activeSwitch = Y,lastUpdatedDt = 2013-08-31,lastUpdatedBy = MAHESH],dueDate = 2013-09 -01,lastUpdatedDt = 2013-09-01,lastUpdatedBy = mahesh]
但是,如果我尝试插入工作方式,
JobVO jobVO = new JobVO();
jobVO.setAuditorId(1);
jobVO.setDueDate(new Date());
jobVO.setJobDesc("VAT1");
jobVO.setJobName("Account");
jobVO.setLastUpdatedBy("Mahesh");
jobVO.setLastUpdatedDt(new Date());
ServiceVO service=new ServiceVO();
service.setServiceId(getClientId());
jobVO.setService(service);
this.sessionFactory.getCurrentSession().persist(jobVO);
出现如下所示的错误,org.springframework.orm.hibernate4.HibernateOptimisticLockingFailureException:批处理更新从更新[0]返回了意外的行数; 实际行数:0; 预期:1; 嵌套的异常是org.hibernate.StaleStateException:批处理更新从更新[0]返回了意外的行数; 实际行数:0; 预期:org.springframework.orm.hibernate4.HibernateTransactionManager.convertHibernateAccessException(HibernateTransactionManager.java:680)处org.springframework.orm.hibernate4.SessionFactoryUtils.convertHibernateAccessException(SessionFactoryUtils.java:181)为1
请帮助我解决此问题。
发生错误是因为有2个事务在同一记录上工作。 如果一个记录被2个事务读取,并且如果该记录首先被一个事务保存,则在第二个事务中将抛出乐观锁定异常,因为系统假定其他人都不会修改该记录。
您是否在批处理模式下使用多线程?
有不同的解决方案:
您具有单向关系。 您必须添加ServiceVO
类:
@OneToOne(fetch = FetchType.LAZY, mappedBy = "service")
private JobVO job;
这段代码创建了双向关系,我认为它可以解决您的问题。
请尝试这个。
ServiceVO service=new ServiceVO();
service.setServiceId(getClientId());
this.sessionFactory.getCurrentSession().saveOrUpdate(service);
JobVO jobVO = new JobVO();
jobVO.setAuditorId(1);
jobVO.setClientId(getClientId());
jobVO.setDueDate(new Date());
jobVO.setJobDesc("VAT1");
jobVO.setJobName("Account");
jobVO.setLastUpdatedBy("Mahesh");
jobVO.setLastUpdatedDt(new Date());
jobVO.setService(service);
this.sessionFactory.getCurrentSession().saveOrUpdate(jobVO);
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