mysql select语句中的内部联接语法错误

Question

这是我的MySQL select语句，我正在尝试做一个交集：

SELECT id 
FROM
(SELECT id 
 FROM members WHERE id!=15 AND `last name` = `last name` AND (`first name` = "James") AND `email address` = `email address` AND `mobile number` = `mobile number` AND type_id = type_id AND active = active
) AS A

INNER JOIN

SELECT id 
FROM
(SELECT DISTINCT m.members_id as id 
 FROM map m 
 WHERE m.members_id!=15 AND (((SELECT count(*) FROM tasks) = 0) OR (((SELECT count(*) FROM checklist WHERE map_id=m.id) / (SELECT count(*) FROM tasks)) * 100 >= 0 AND ((SELECT count(*) FROM checklist WHERE map_id=m.id) / (SELECT count(*) FROM tasks)) * 100 <= 100)) AND m.`topic` = m.`topic` AND m.`location` = m.`location` AND m.`country` = m.`country` AND m.`city` = m.`city` AND m.`organization` = m.`organization`
) AS B

USING (id)

这是我从中看到的示例相交代码

SELECT DISTINCT value FROM table_a
INNER JOIN table_b
USING (value);

来自： MySQL中相交的替代方法

但是我在“内部联接”附近收到语法错误。 有人知道这是怎么回事吗？

Answer 1

一些事情：

1. 您的Where子句在连接之后出现-这可能是您的问题
2. 难以理解您正在使用的某些字段名称发生了什么
3. 要尝试修复格式问题并提供其他建议，但这很难阅读。

只是让您的查询看起来像您用作模板的查询，我希望结果是这样的：

SELECT id 
FROM
(SELECT id 
 FROM members WHERE id!=15 AND `last name` = `last name` AND (`first name` = "James") AND `email address` = `email address` AND `mobile number` = `mobile number` AND type_id = type_id AND active = active
) AS A

INNER JOIN

(SELECT DISTINCT m.members_id as id 
 FROM map m 
 WHERE m.members_id!=15 AND (((SELECT count(*) FROM tasks) = 0) OR (((SELECT count(*) FROM checklist WHERE map_id=m.id) / (SELECT count(*) FROM tasks)) * 100 >= 0 AND ((SELECT count(*) FROM checklist WHERE map_id=m.id) / (SELECT count(*) FROM tasks)) * 100 <= 100)) AND m.`topic` = m.`topic` AND m.`location` = m.`location` AND m.`country` = m.`country` AND m.`city` = m.`city` AND m.`organization` = m.`organization`
) AS B

USING (id)

内部联接后，从中删除该选择ID。 也就是说，您可以简化查询并查看是否可以首先使用它-子选择中有很多条件逻辑，这使得很难在小提琴中进行测试，等等。也许发布小提琴作为您的示例数据和查询？