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[英]What is the best way to connect to and query a MySQL database using PHP?
[英]what is the best way to connect an iOS client to a MySql database using PHP?
我有MySql数据,我想从iOS提取数据
<?php
// Database credentials
$host = 'localhost';
$db = 'json';
$uid = 'json';
$pwd = 'json1';
// Connect to the database server
$link = mysql_connect($host, $uid, $pwd) or die("Could not connect");
//select the json database
mysql_select_db($db) or die("Could not select database");
// Create an array to hold our results
$arr = array();
//Execute the query
$rs = mysql_query("SELECT id,userid,firstname,lastname,email FROM users");
// Add the rows to the array
while($obj = mysql_fetch_object($rs)) {
$arr[] = $obj;
}
//return the json result. The string users is just a name for the container object. Can be set anything.
echo '{"users":'.json_encode($arr).'}';
?>
将iOS连接到MySql数据库的最佳方法是什么?
请帮忙 !!
是的,这很好,但只需添加
header('Content-Type: application/json');
到php,以便响应为json而不是html。
您可以添加一些验证或错误处理,例如,
try
{
//Your DB query part
// Connect to the database server
$link = mysql_connect($host, $uid, $pwd) or die("Could not connect");
//select the json database
mysql_select_db($db) or die("Could not select database");
// Create an array to hold our results
$arr = array();
//Execute the query
$rs = mysql_query("SELECT id,userid,firstname,lastname,email FROM users");
// Add the rows to the array
while($obj = mysql_fetch_object($rs)) {
$arr[] = $obj;
}
//return the json result. The string users is just a name for the container object. Can be set anything.
if(count($arr) >0)
{
echo '{"users":'.json_encode($arr).'}';
}
}
catch(PDOException $e) {
echo '{"error":{"text":'. $e->getMessage() .'}}';
}
}
创建一个NSURLConnection类,该类与托管此.php文件的服务器进行通信;如果您使用JSON解析器或内置的NSJSONSerialization类,可以为您解析响应。 您在这里要做的是创建iOS应用用来与您的数据库对话的Web服务,特别是查询。 如果要扩大规模,则应尝试实现SLIM或FAT-FREE之类的框架。
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