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[英]SELECT min max and max min value from a part of a table in MySQL
[英]Select max,min, last value from a column in mysql table
表格式
id time_stamp
3 2013-09-05 12:00:00
5 2013-09-06 12:00:00
12 2013-09-07 12:00:00
2 2013-09-08 12:00:00
5 2013-09-09 12:00:00
8 2013-09-10 12:00:00
从上面的表中我想在单个mysql select查询语句中选择min(id),max(id),last id,last time_stamp
需要的输出是:
min max last(val) last(time_stamp)
2 12 8 2013-09-09 12:00:00
我使用了以下查询
select id, min(id),max(id), time_stamp from table order by time_stamp limit 1
我得到错误的最新id值3而不是8
如果低于SQL小提琴,请检查此项
http://www.sqlfiddle.com/#!2/e9cb1/2/0
这是一个方法,使用substring_index()
/ group_concat()
技巧:
select min(id), max(id),
substring_index(group_concat(id order by time_stamp desc), ',', 1) as lastid
from table ;
假设您在问题中错误地提到了最后一个(time_stamp) - 像往常一样获取max,min,然后找出子查询中的最后一个id和时间戳,然后可以JOIN将所有结果放在一行中。
MySQL 5.5.32架构设置 :
create table t (id int, time_stamp datetime);
insert into t values(3, '2013-09-05 12:00:00');
insert into t values(5, '2013-09-06 12:00:00');
insert into t values(12, '2013-09-07 12:00:00');
insert into t values(2, '2013-09-08 12:00:00');
insert into t values(5, '2013-09-09 12:00:00');
insert into t values(8, '2013-09-10 12:00:00');
查询1 :
SELECT MIN(t.id), MAX(t.id), latest.id, latest.time_stamp
FROM t JOIN (
SELECT t.id, t.time_stamp
FROM t
ORDER BY time_stamp DESC
LIMIT 1) latest
结果 :
| MIN(T.ID) | MAX(T.ID) | ID | TIME_STAMP |
|-----------|-----------|----|----------------------------------|
| 2 | 12 | 8 | September, 10 2013 12:00:00+0000 |
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