如何传递数据以隐藏和显示“完整”功能

Question

我需要做这样的事情：

for (var i in arrayOfObjects) {
    var options = arrayOfObjects[i];
    $('.' + options.className).hide('middle', function(){
        //And here I need to use a data from options. 
        //How can I pass 'options' object here? 
        $(options.attribute).doSomethig();
    });
}

Answer 1

这是因为您在异步回调方法中使用了关闭变量options 。 一种解决方案是在循环内部创建私有闭包，如下所示

for (var i in arrayOfObjects) {
    (function(options){
        $('.' + options.className).hide('middle', function () {
            //And here I need to use a data from options. 
            //How can I pass 'options' object here? 
            $(options.attribute).doSomethig();
        });
    })(arrayOfObjects[i])
}

另一个解决方案是使用jQuery进行迭代

$.each(arrayOfObjects, function(i, options){
    $('.' + options.className).hide('middle', function () {
        //And here I need to use a data from options. 
        //How can I pass 'options' object here? 
        $(options.attribute).doSomethig();
    });
})