[英]MySQL Select one row with unique attribute value
我正在建立一个库存系统,并决定将每种产品的余额(每次更新)存储到下表中:
+------------+--------------+---------+------+
| Product_id | Warehouse_id | Balance | Date |
+------------+--------------+---------+------+
例:
工作人员将10件商品添加到Warehouse_id 5中的product_id 123
+------------+--------------+---------+-------------+
| Product_id | Warehouse_id | Balance | Date |
+------------+--------------+---------+-------------+
| 123 | 5 | 10 | 2013-09-16 |
+------------+--------------+---------+-------------+
然后,工作人员将3件商品添加到Warehouse_id 5中的产品234中,并将5件商品添加到Warehouse_id 5中的123中,
+------------+--------------+---------+-------------+
| Product_id | Warehouse_id | Balance | Date |
+------------+--------------+---------+-------------+
| 123 | 5 | 10 | 2013-09-16 |
| 234 | 5 | 3 | 2013-09-18 |
| 123 | 5 | 15 | 2013-09-21 |
+------------+--------------+---------+-------------+
*注意日期栏
现在让我再添加几行
+------------+--------------+---------+-------------+
| Product_id | Warehouse_id | Balance | Date |
+------------+--------------+---------+-------------+
| 123 | 5 | 10 | 2013-09-16 |
| 234 | 5 | 3 | 2013-09-18 |
| 123 | 5 | 15 | 2013-09-21 |
| 123 | 5 | 18 | 2013-09-24 |
| 234 | 5 | 10 | 2013-09-26 |
| 123 | 5 | 22 | 2013-09-29 |
+------------+--------------+---------+-------------+
我如何运行查询以获取截至2013年9月25日所有产品的余额?
这意味着我需要以下结果:
+------------+--------------+---------+-------------+
| Product_id | Warehouse_id | Balance | Date |
+------------+--------------+---------+-------------+
| 234 | 5 | 3 | 2013-09-18 |
| 123 | 5 | 18 | 2013-09-24 |
+------------+--------------+---------+-------------+
简而言之,我需要每个product_id最新的行(按日期)。
任何帮助将不胜感激!
假设每个仓库都保持着产品的余额,您可以这样做
SELECT t.product_id, t.warehouse_id, t.balance, t.date
FROM table1 t JOIN
(
SELECT warehouse_id, product_id, MAX(date) date
FROM table1
WHERE date <= '2013-09-25'
GROUP BY warehouse_id, product_id
) q
ON t.warehouse_id = q.warehouse_id
AND t.product_id = q.product_id
AND t.date = q.date
输出:
| PRODUCT_ID | WAREHOUSE_ID | BALANCE | DATE | |------------|--------------|---------|------------| | 234 | 5 | 3 | 2013-09-18 | | 123 | 5 | 18 | 2013-09-24 |
这是SQLFiddle演示
SELECT *
FROM TABLE
WHERE (PRODUCT_ID, DATE) IN
(SELECT PRODUCT_ID, MAX(DATE) FROM TABLE
WHERE DATE <= '2013-09-25'
GROUP BY PRODUCT_ID )
查询:
SELECT *
FROM table1 t
WHERE t.`Date` = (SELECT MAX(t2.`Date`)
FROM Table1 t2
WHERE t2.`Date` <= '2013-09-25'
AND t2.product_id = t.product_id)
声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.