[英]SQL Sum sub-query with joined tables?
我有一个论坛站点,其中包含帖子(gems)和文件附件(gemdetail)以及对帖子的回复(gems),并且回复中还可以包含文件附件(gemdetail)。 由于帖子和回复都存储在同一表中,因此可以进行有趣的左联接,该联接选择具有关联的回复和详细信息的所有帖子。
我想向混合(评分)添加另一个表,该表允许用户对每个帖子进行评分。 然后,我希望能够在同一查询中获得每个帖子的总评分。 如何将sum(rating)相加,以便输出的每一行都有gemid的总和。 我知道我需要一个总和子查询(带有临时结果集的派生表),类似于此处找到的子查询,但它超出了我的技能范围。 提前致谢。
表结构如下
table: gems
gemid title replygemid
----- ----- ----------
220 map NULL
223 inhabitants NULL
403 reply to map 220
table: gemdetail
gemid filename
------ --------
220 uganda-map.jpg
220 mozambique-map.jpg
223 uganda-inhabitants.jpg
223 kenya-inhabitants.jpg
403 mona-lisa-x8.jpg
table: rating (to be added)
gemid rating
----- -------
220 1
220 5
223 3
403 -1
我当前的(简体)查询
SELECT g.gemid as ggemid, g.title as gtitle, gemdetail.filename as gfilename, r.filename as rfilename
FROM (SELECT gems.* FROM gems ) g
LEFT JOIN
(SELECT title, x.gemid, x.replygemid, x.userid, y.filename from gems x
LEFT JOIN gemdetail y ON x.gemid = y.gemid ) r ON g.gemid = r.replygemid
LEFT JOIN gemdetail ON g.gemid = gemdetail.gemid
结果可能如下所示
ggemid replygemid gtitle gfilename rfilename
------ ---------- ------ --------------------- ----------------
220 403 Map uganda-map.jpg mona-lisa-x8.jpg
220 403 Map mozambique-map.jpg mona-lisa-x8.jpg
223 NULL Inhabitants uganda-inhabitants.jpg NULL
223 NULL Inhabitants kenya-inhabitants.jpg NULL
223 NULL Inhabitants kenya-inhabitants.jpg NULL
我认为这是您想要的:
SELECT g.gemid as ggemid, g.title as gtitle, gemdetail.filename as gfilename, r.filename as rfilename, rt.sum_rating
FROM (SELECT gems.* FROM gems ) g
LEFT JOIN
(SELECT title, x.gemid, x.replygemid, x.userid, y.filename from gems x
LEFT JOIN gemdetail y ON x.gemid = y.gemid ) r ON g.gemid = r.replygemid
LEFT JOIN gemdetail ON g.gemid = gemdetail.gemid
LEFT JOIN (SELECT gemid, SUM(rating) as sum_rating from rating GROUP BY gemid) rt ON g.gemid = rt.gemid
查询 :
SELECT g.gemid as ggemid, g2.gemid as replygemid,
g.title as gtitle, gd.filename as gfilename,
gd2.filename as rfilename, SUM(rating) as rating
FROM gems g
INNER JOIN gemdetail gd ON g.gemid = gd.gemid
INNER JOIN rating r ON g.gemid = r.gemid
LEFT OUTER JOIN gems g2 ON g.gemid = g2.replygemid
LEFT OUTER JOIN gemdetail gd2 ON g2.gemid = gd2.gemid
GROUP BY g.gemid, g2.gemid, g.title,
gd.filename, gd2.filename
结果 :
| GGEMID | REPLYGEMID | GTITLE | GFILENAME | RFILENAME | RATING |
|--------|------------|--------------|------------------------|------------------|--------|
| 220 | 403 | map | mozambique-map.jpg | mona-lisa-x8.jpg | 6 |
| 220 | 403 | map | uganda-map.jpg | mona-lisa-x8.jpg | 6 |
| 223 | (null) | inhabitants | kenya-inhabitants.jpg | (null) | 3 |
| 223 | (null) | inhabitants | uganda-inhabitants.jpg | (null) | 3 |
| 403 | (null) | reply to map | mona-lisa-x8.jpg | (null) | -1 |
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