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如何使用ORACLE JOB SCHEDULER更改禁用或启用触发器

[英]how to alter disable or enable trigger with ORACLE JOB SCHEDULER

在作业调度程序的job_action中,我具有以下SQL

'BEGIN
       ALTER TRIGGER AFTERIUDSETTLEMENTS DISABLE;
       ALTER TRIGGER AFTERIUDLIQUIDATIONSDETAILS DISABLE;
       UPDATE APPOINTSOFCAS A SET INLD = (SELECT COUNT(*) FROM LIQUIDATIONSDETAILS LD WHERE A.CUSTOMERID = LD.CUSTOMERID AND A.ID = LD.APPOINTOFCAID AND A.KINDCONTROLID = LD.KINDCONTROLID);
       UPDATE APPOINTSOFCAS A SET INSD = (SELECT COUNT(*) FROM SETTLEMENTS S WHERE A.CUSTOMERID = S.CUSTOMERID AND A.ID = S.APPOINTOFCAID AND A.KINDCONTROLID = S.KINDCONTROLID);
COMMIT;
       ALTER TRIGGER AFTERIUDSETTLEMENTS ENABLE;
       ALTER TRIGGER AFTERIUDLIQUIDATIONSDETAILS ENABLE;                            
END;'

但是运行后,作业失败,并出现以下错误:

ORA-06550: γραμμή 2, στήλη 29:

PLS-00103:预期以下情况之一时遇到符号“ ALTER”:

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 <a double-quoted delimited-identifier> <a bind variable> <<
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οριστική διαγραφή

可以在作业调度程序中禁用或启用触发器?

ALTER语句是DDL,这意味着如果不使用EXECUTE IMMEDIATE ,就不能在PL / SQL块的范围内完成它。

这是非常不寻常的,这意味着您的触发器在每个会话中都处于禁用状态,因此,如果发生其他情况,它们将不会触发任何更改。 有可能,但这只是感觉不对。

您也可以在一个语句中进行两次更新,这将提高效率。

begin

   execute immediate 'alter trigger afteriudsettlements disable';
   execute immediate 'alter trigger afteriudliquidationsdetails disable';

   update appointsofcas a 
      set inld = ( select count(*) 
                     from liquidationsdetails ld 
                    where a.customerid = ld.customerid 
                      and a.id = ld.appointofcaid 
                      and a.kindcontrolid = ld.kindcontrolid )
        , insd = ( select count(*) 
                     from settlements s 
                    where a.customerid = s.customerid 
                      and a.id = s.appointofcaid 
                      and a.kindcontrolid = s.kindcontrolid );

   commit;

   execute immediate 'alter trigger afteriudsettlements enable';
   execute immediate 'alter trigger afteriudliquidationsdetails enable';

end;
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